Answer:
9 I think
Step-by-step explanation:
I added 5 plus 4 to get 9 but I'm really not sure but I hope i helped!
Answer:
40+99
139
Step-by-step explanation:
Answer:
7.177%
Step-by-step explanation:
2 is double
2 =( 1 + i)^10 solve for i = 7.177%
-2x+6y=6
-7x+8y=-5
2(7x+8y=-5)
-7(-2x+6y=6)
Distribute
14x+16y=-10
14x-42y=-42
eliminate
-26y=-32
divide
y=1.2
-2x+6(1.2)=6
-2x+7.4=6
subtract 7.4 on both sides
-2x=-1.4
divide
x=0.7
I believe this is right
Answer:
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
Step-by-step explanation:
Given



See attachment for spinner
Required
![P(Cube \ge 5\ and\ Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29)
On a number cube, we have:
---- i.e. 2 outcomes
So, the probability is:



On the spinner, we have:
---- i.e. 1 outcomes
So, the probability is:
![P(Spin[A]) = \frac{n(Spin[A])}{n(Spinner)}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7Bn%28Spin%5BA%5D%29%7D%7Bn%28Spinner%29%7D)
![P(Spin[A]) = \frac{1}{8}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B8%7D)
is calculated as thus:
![P(Cube \ge 5\ and\ Spin[A]) = P(Cube \ge 5) * P(Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20P%28Cube%20%5Cge%205%29%20%2A%20P%28Spin%5BA%5D%29)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{3} * \frac{1}{8}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%5Cfrac%7B1%7D%7B8%7D)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)