1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
4 years ago
13

Describe a real world situation that can be represented using a table and a graph

Mathematics
1 answer:
Wittaler [7]4 years ago
3 0
One real situation represented with a table is like amount of exercise in a week. in a graph it can be like if it increases or decreased each day. hope this helps!
You might be interested in
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
Ostrovityanka [42]

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

f(x) = \sqrt{x}

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

f^i(c) = \frac{f(b) - f(a)}{b -a }

After this,

f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ =  \frac{1}{2}x ^{\frac{-1}{2}

f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\

After this,

Put the values of a and b to the above equation

f^i(c) = \frac{f(b) - f(a)}{b - a}  \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0}  \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}

= 2.25

4 0
3 years ago
I need help with this problemmmm.
AlladinOne [14]

Answer:

x = 1 1/6, x = 1.16

There you go! :D

3 0
3 years ago
Read 2 more answers
What does pi equal exactly
Scilla [17]
3.141562.... And it goes on and on and on
6 0
3 years ago
Read 2 more answers
A right triangle has legs that measure 7 cm and 6 cm. What is the length of the hypotenuse in meters?
dalvyx [7]
<h2>Greetings!</h2>

Answer:

\sqrt{85}  or 9.22

Step-by-step explanation:

You need to remember the following equation:

a^{2} + b^{2} = c^{2}

Where a and b is the lengths of the two sides and c is the hypotenuse.

So simply plug these values into this:

6^{2} + 7^{2} = h^{2}

36 + 49 = h^2

36 + 49 = 85

So the hypotenuse is the square root of 85:

\sqrt{85}  = 9.22


<h2>Hope this helps!</h2>
7 0
3 years ago
Use the x-intercept method to find all real solutions of the equation.<br> x^3-8x^2+9x+18=0
meriva

Answer:

a. x=-1,3,\:or\:6

Step-by-step explanation:

The given equation is;

x^3-8x^2+9x+18=0

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.

The corresponding function is

f(x)=x^3-8x^2+9x+18

The solution to x^3-8x^2+9x+18=0 is where the graph touches the x-axis.

We can see from the graph  that; the x-intercepts are;

(-1,0),(3,0) and (6,0).

Therefore the real solutions are:

x=-1,3,\:or\:6

8 0
4 years ago
Read 2 more answers
Other questions:
  • The value of y varies inversely as the square of x, and y=4, when x=3.
    14·1 answer
  • How are fraction and decimals related
    15·2 answers
  • Ind all integers b such that x^(2)+bx+5 can be factored.
    15·2 answers
  • The function f is defined by f(x)=200÷x−b, where b is a constant. Find b, if the value of f at x= 1/3 is equal to 150.
    12·1 answer
  • What is the place value for 0?
    5·1 answer
  • Math help, for geometry,, PLEASE HELP :((( !!!
    11·1 answer
  • In a school of 450 students, 110 of them are in the choir, 240 of them are in the band and 60 students are in the choir and the
    6·1 answer
  • I need help!!!!!!!!!
    12·1 answer
  • The science club is going to the space museum. The club consists of 27 students.
    5·1 answer
  • Check all that apply. if cos0 = 13/5, then: ?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!