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igomit [66]
3 years ago
10

Given: g(x) = 2x2 + 3x + 10

Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

x = 3.576 and x = - 3.076

Step-by-step explanation:

Two functions are given to be, g(x) = 2x² + 3x + 10 and k(x) = 2x + 16.

Now, we have to solve the equation g(x) = 2k(x)  

⇒ 2x² + 3x + 10 = 4x + 32

⇒2x² - x - 22 = 0

The expression in the left hand side can not be factorized and therefore we have to use Sridhar Acharya formula which gives the solutions of the equation in the form ax² + bx + c = 0 are given by  

x = \frac{-b + \sqrt{b^{2} - 4ac} }{2a} and x = \frac{-b - \sqrt{b^{2} - 4ac} }{2a}

Therefore, the solutions of the given equation are  

x = \frac{-(- 1) + \sqrt{(- 1)^{2} - 4 (2)(-22)}  }{2(2)} = 3.576

and x = \frac{-(- 1) - \sqrt{(- 1)^{2} - 4 (2)(-22)}  }{2(2)} = -3.076 (Answer)

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Which monomials are perfect squares? Select three options.
aliya0001 [1]

Answer:

a, d and e.

Step-by-step explanation:

A perfect square is one where the coefficient is a perfect square and the exponent is even.

So they are 25x^12, 36x^16 and 9x^8.

4 0
3 years ago
According to historical records, the Great Pyramid of Giza was originally about 147 meters tall. Assuming it was built with its
vivado [14]

Answer:

115m

Step-by-step explanation:

Note that one of the face of a pyramid is a right angled triangle.

Since the pyramid was about 147m tall, the height of triangle will be 147m. If one of the faces is built with one of its faces at 52° to the incline, we can find the original length of one of its sides using SOH CAH TOA

tan(theta) = opposite/adjacent

Given theta = 52°, opposite = 147m (the side directly opposite the angle)

Substituting we have;

Tan52° = 147/adjacent

Adjacent = 147/tan52°

Adjacent = 114.8m

= 115m

Therefore 115m is the original length of one of its side

6 0
4 years ago
Find the equation of a line that is perpendicular to 4x+6y=1 that has a greater y intercept compared to 2x+3y=18
Marina86 [1]

Answer:

4y = 6x + 40

Step-by-step explanation:

The general equation of a straight line is y = mx + b

m is the slope and b is the y-intercept

let us write both equations in this form;

we have this as;

6y = -4x + 1

y = -4x/6 + 1/6

and;

2x + 3y = 18

3y = -2x + 18

y = -2x/3 + 6

So firstly we want to find an equation that is perpendicular to the first

When two lines are perpendicular, their slopes has a product of -1

The slope of the first line is -4/6

let the slope of the line we want be m

As per they are perpendicular;

-4/6 * m = -1

-4m/6 = -1

-4m = -6

m = 6/4

So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6

we can choose 10

and we have the equation as:

y = 6x/4 + 10

multiply through by 4

4y = 6x + 40

7 0
3 years ago
I need help! THIS IS NOT MULTIPLE CHOICE!!!! The time needed to roast a chicken depends on its weight. Allow at least 20 min/lb
vladimir2022 [97]
What would you do if you ever needed to cook a chicken
if y is the time required to cook the bird and x is number of chicken lbs

y = 20x when x ≤ 6
y = 15x when x > 6

To Graph:
Have the y-axis (minutes) go by 5's since slopes of both equations are multiples of 5. The y-axis, I would suggest go to atleast 150 minutes for a 10 lbs chicken. The x-axis is in lbs and can go by 1 lb marks.

Start with the first equation where the chicken is smaller than or equal to 6 lbs. (0,0) (1,20), (2,40) (3, 60), (4,80), (5,100) to 6lbs (6,120). If the equation is EQUAL TO the point and the line will be SOLID.

for the second equation, the chicken is larger than 6 lbs. Start with x = 6 but the point will be OPEN and the line DASHED because it's NOT EQUAL TO. (6,90) (7,105) (8,120) (9,135), (10, 150) .... and on arrow to show this

7 0
3 years ago
Determine the area of the following figures.
Katyanochek1 [597]
A = bh
A = 8 x 7 = 56 cm^2

----------------------------------------
8 0
3 years ago
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