Based on the knowledge of Erikson’s theory of psychosocial development, we can see that the 6 year old son is at the stage of:
- School-age – Industry versus inferiority.
On the other hand, the 5 month old daughter is at the stage of
- Infancy – Basic trust versus mistrust.
<h3>Erikson’s theory of psychosocial development</h3>
This states that there is an order through which humans develop and adapt as they grow from Infancy till adulthood and he summarised these stages into eight parts.
We can see that the 6 year old son is at the School age stage where he has Industry vs inferiority as he compares himself with his class mates while the 5 month old daughter is at the Infancy stage where she is learning how to move about and responds to certain stimuli.
Read more about cognitive development here:
brainly.com/question/9741540
Answers:
1) The first quartile (Q₁) = 11 ; 2) The median = 38.5 ;
3) The third quartile (Q₃) = 45 ;
4) The difference of the largest value and the median = 10.5 .
_______
Explanation:
Given this data set with 8 (eight) values: → {6, 47, 49, 15, 43, 41, 7, 36};
→Rewrite the values in increasing order; to help us find the median, first quartile (Q,) and third quartile (Q₃) : → {6, 7, 15, 36, 41, 43, 47, 49}.
→We want to find; or at least match; the following 4 (four) values [associated with the above data set] — 38.5, 11, 10, 45 ;
1) The first quartile (Q₁); 2) The median; 3) The third quartile (Q₃); &
4) The difference of the largest value and the median.
Note: Let us start by finding the "median". This will help us find the correct values for the descriptions in "Numbers 2 & 4" above.
The "median" would be the middle number within a data set, when the values are placed in smallest to largest (or, largest to smallest). However, our data set contains an EVEN number [specifically, "8" (eight)] values. In these cases , we take the 2 (two) numbers closest to the middle, and find the "mean" of those 2 (two) numbers; and that value obtained is the median. So, in our case, the 2 (two) numbers closest to the middle are:
"36 & 41". To get the "mean" of these 2 (two) numbers, we add them together to get the sum; and then, we divide that value by "2" (the number of values we are adding):
→ 36 + 41 = 77; → 77/2 = 38.5 ; → which is the median for our data set; and is a listed value.
→Now, examine Description "(#4): The difference of the largest value and the median"—(SEE ABOVE) ;
→ We can calculate this value. We examine the values within our data set to find the largest value, "49". Our calculated "median" for our dataset, "38.5". So, to find the difference, we subtract: 49 − 38.5 = 10.5 ; which is a given value".
→Now, we have 2 (two) remaining values, "11" & "45"; with only 2 (two) remaining "descriptions" to match;
→So basically we know that "11" would have to be the "first quartile (Q₁)"; & that "45" would have to be the "third quartile (Q₃)".
→Nonetheless, let us do the calculations anyway.
→Let us start with the "first quartile"; The "first quartile", also denoted as Q₁, is the median of the LOWER half of the data set (not including the median value)—which means that about 25% of the numbers in the data set lie below Q₁; & that about 75% lie above Q₁.).
→Given our data set: {6, 7, 15, 36, 41, 43, 47, 49};
We have a total of 8 (eight) values; an even number of values.
The values in the LOWEST range would be: 6, 7, 15, 36.
The values in the highest range would be: 41, 43, 47, 49.
Our calculated median is: 38.5 . →To find Q₁, we find the median of the numbers in the lower range. Since the last number of the first 4 (four) numbers in the lower range is "36"; and since "36" is LESS THAN the [calculated] median of the data set, "38.5" ; we shall include "36" as one of the numbers in the "lower range" when finding the "median" to calculate Q₁
→ So given the lower range of numbers in our data set: 6, 7, 15, 36 ;
We don't have a given "median", since we have an EVEN NUMBER of values. In this case, we calculate the MEDIAN of these 4 (four) values, by finding the "mean" of the 2 (two) numbers closest to the middle, which are "7 & 15". To find the mean of "7 & 15" ; we add them together to get a sum;
then we divide that sum by "2" (i.e. the number of values added up);
→ 7 + 15 = 22 ; → 22 ÷ 2 = 11 ; ↔ Q₁ = 11.
Now, let us calculate the third quartile; also known as "Q₃".
Q₃ is the median of the last half of the higher values in the set, not including the median itself. As explained above, we have a calculated median for our data set, of 38.5; since our data set contains an EVEN number of values. We now take the median of our higher set of values (which is Q₃). Since our higher set of values are an even number of values; we calculate the median of these 4 (four) values by taking the mean of the 2 (two) numbers closest to the center of the these 4 (four) values. This value is Q₃. →Given our higher set of values: 41, 43, 47, 49 ; → We calculate the "median" of these 4 (four) numbers; by taking the mean of the 2 (two) numbers in the middle; "43 & 47".
→ Method 1): List the integers from "43 to 47" ; → 43, 44, 45, 46, 47;
→ Since this is an ODD number of integers in sequential order;
→ "45" is not only the "median"; but also the "mean" of (43 & 47);
thus, 45 = Q₃;
→ Method 2): Our higher set of values: 41, 43, 47, 49 ;
→ We calculate the "median" of these 4 (four) numbers; by taking the
"mean" of the 2 (two) numbers in the middle; "43 & 47"; We don't have a given "median", since we have an EVEN NUMBER of values. In this case, we calculate the MEDIAN of these 4 (four) values, by finding the mean of the 2 (two) numbers closest to the middle, which are "43 & 47." To find the mean of "43 & 47"; we add them together to get a sum; then we divide that sum by "2" (i.e. the number of values added);
→ 43 + 47 = 90 ; → 90 ÷ 2 = 45 ; → 45 = Q₃ .
Chocolate <span>is made in the form of a liquid, paste, or in a block, or used as a flavoring ingredient in other foods.
</span><span>Harvesting
</span>Fermenting: The pods and pulp are placed into large wooden containers, where the pulp is allowed to ferment for five to seven days. During the process, the beans are turned to help them ferment more evenly. This is the first stage in developing the flavour of the chocolate.
Drying
After fermentation, the next step in the process is to dry the beans. This is usually done by spreading them out into a single layer in the sun. Most beans are transferred into sacks and transported around the world after drying, so in order to prevent mold, it’s important that they’re completely dry at this point.
<span>Roasting
</span>Cracking & Winnowing
The roasted cocoa beans have a thin, papery shell around them which needs to be removed, so at this point in the process, the beans are cracked open and the shell is removed in a process called winnowing. The lighter shells are blown away with fans, leaving behind pieces of pure cocoa bean, known as “nibs”.
Grinding & Conching
The cocoa nibs are ground with stone rollers until they become a paste known as cocoa mass or cocoa liquor. This pure, unrefined form of chocolate contains both cocoa solids (the chocolatey part!) and cocoa butter (the natural fat present in the bean).Cocoa butter can be extracted from the cocoa mass with a hydraulic press. This is useful because most chocolate makers often use extra cocoa butter to give their chocolate a smoother, glossier texture.
And this is how you get yummy chocolate.
Hope this helps!
Answer:
A thousand years spoked wheels allowed heavy carts to evolve into light carts, or chariots. These may have been developed first to help the people herd their horses, or for hunting; they were soon being used for war, and were to have a far-reaching impact on the civilizations of the Middle East and China.