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scoray [572]
4 years ago
11

Idk how to solve it...

Mathematics
1 answer:
strojnjashka [21]4 years ago
8 0
|-6b| <= 60

b <= 60/6 
b<= 10

and 

b>= 60/-6
b>= -10

answer:
b>= - 10 and b<= 10
or 
-10 <= b <= 10 
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You have two pieces for fabric. One piece is 6 feet wide and the other piece is 7.5 feet wide. You want to cut both pieces into
My name is Ann [436]

Answer:

<em>Strips should be </em><em>1.5 ft wide.</em>

Step-by-step explanation:

Given:

Width of 1st piece = 6 ft

Width of 2nd piece = 7.5 ft

To find:

To find the maximum width possible to make strips of equal size from both the pieces.

Solution:

This problem can be visualized as if we are given two numbers and we have to find the Highest common factor for both of them i.e. HCF of 6 and 7.5 will be our answer.

Let us try to factorize the given factors:

7.5 = 3 \times 2.5 = \underline {3 \times 0.5} \times 5

6 = 3 \times 2 = \underline {3 \times 0.5 }\times 2

The common factors are highlighted above as underlined.

Therefore, the answer is 3 \times 0.5 = <em>1.5 ft </em>

<em></em>

<em>Strips should be </em><em>1.5 ft wide.</em>

5 0
3 years ago
What is the image point of (9,9) after a translation right 5 units and down 4 units?
Alona [7]

Answer:

the answer is (4,5)

Step-by-step explanation:

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7 0
4 years ago
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Mrs. Poster's class is divided into three groups of students. Each group has 3 girls and 2 boys, Which expression could she use
natka813 [3]

Answer:

3 X (2+3)

Step-by-step explanation:

If we have five students (3 girls and 2 boys), and three groups, we can use the expression 3 X (2+3), which concludes three groups times five students (in each group), which will give us our total of 15 students.

6 0
3 years ago
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
Artemon [7]

Answer:

a) The height decreases at a rate of \frac{7}{12} ft/sec.

b) The area increases at a rate of \frac{527}{24} ft^2/sec

c) The angle is increasing at a rate of \frac{1}{12} rad/sec

Step-by-step explanation:

Attached you will find a sketch of the situation. The ladder forms a triangle of base b and height h with the house. The key to any type of problem is to identify the formula we want to differentiate, by having in mind the rules of differentiation.

a) Using pythagorean theorem, we have that 25^2 = h^2+b^2. From here, we have that

h^2 = 25^2-b^2

if we differentiate with respecto to t (t is time), by implicit differentiation we get

2h \frac{dh}{dt} = -2b\frac{db}{dt}

Then,

\frac{dh}{dt} = -\frac{b}{h}\frac{db}{dt}.

We are told that the base is increasing at a rate of 2 ft/s (that is the value of db/dt). Using the pythagorean theorem, when b = 7, then h = 24. So,

\frac{dh}{dt} = -\frac{2\cdot 7}{24}= \frac{-7}{12}

b) The area of the triangle is given by

A = \frac{1}{2}bh

By differentiating with respect to t, using the product formula we get

\frac{dA}{dt} = \frac{1}{2} (\frac{db}{dt}h+b\frac{dh}{dt})

when b=7,  we know that h=24 and dh/dt = -1/12. Then

\frac{dA}{dt} = \frac{1}{2}(2\cdot 24- 7\frac{7}{12}) = \frac{527}{24}

c) Based on the drawing, we have that

\sin(\theta)= \frac{b}{25}

If we differentiate with respect of t, and recalling that the derivative of sine is cosine, we get

\cos(\theta)\frac{d\theta}{dt}=\frac{1}{25}\frac{db}{dt} or, by replacing the value of db/dt

\frac{d\theta}{dt}=\frac{2}{25\cos(\theta)}

when b = 7, we have that h = 24, then \cos(\theta) = \frac{24}{25}, then

\frac{d\theta}{dt} = \frac{2}{25\frac{24}{25}} = \frac{2}{24} = \frac{1}{12}

7 0
3 years ago
How can I solve this question???
eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

360\°/5=72\°

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

5 0
3 years ago
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