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LUCKY_DIMON [66]
3 years ago
10

Which equation has an a-value of –2, a b-value of 1, and a c-value of 3? 0 = –2x2 + x + 3 0 = 2x2 + x + 3 0 = –2x2 + 3 0 = 2x2 –

x + 3
Mathematics
1 answer:
Zolol [24]3 years ago
6 0

ax² + bx + c = 0

You know:

a = -2

b = 1

c = 3

The 1st option is your answer

-2x² + x + 3 = 0

a = -2

b = 1

c = 3

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Answer:

(0, -3) and (2, 1)

Step-by-step explanation:

There are 5 points marked on the graph: (±2, 1), (±1, -2) and (0, -3). These are solutions to the equation describing the function:

... y = x² - 3

Apparently, you are being asked to report the coordinates of any two of these points.

_____

<em>Comment on the problem</em>

The wording "solutions to the function" is a bit odd. An equation has solutions—values of the variables that make it be true. A function is a relationship between values, a definition. There is nothing  to solve.

In the above we have assumed the intent is to find (x, y) pairs that match the function definition. Sometimes, we're interested in values of x that make y be zero. (x, y) = (±√3, 0) It isn't obvious what the intent of this question is.

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Read 2 more answers
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