5x+17=-8 solve the equation

What is the area of the triangle?

Advocard [28]

Answer:

32

Step-by-step explanation:

The area A of a triangle is given by the formula A=12bh where b is the base and h is the height of the triangle.

6 0

3 years ago

Which is the solution to the equation 8.25 + 1/4 W = 10.75? Round to the nearest hundredth if necessary.

murzikaleks [220]

$8.25+\dfrac{1}{4}w=10.75\ \ \ \ |-8.25\\\\\dfrac{1}{4}w=2.5\ \ \ |\cdot4\\\\w=10$

3 0

3 years ago

When planning road development, the road commission estimates the future population using the function represented in the table,

Leokris [45]

Considering that 160,000 is the y-intercept of the function, it's significance is given by:

the initial population at the time of the estimation.

<h3>What is the y-intercept of a function f(x)?</h3>

The y-intercept is f(0), that is, the value of y when x = 0, which is interpreted as the initial value of the function.

Researching this problem on the internet, it is found that f(0) = 160,000, hence the significance of 160,000 in the function is given by:

the initial population at the time of the estimation.

More can be learned about the y-intercept of a function at brainly.com/question/27979095

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7 0

2 years ago

Need help plz help i need to get this done

Leona [35]

Answer:

42

Step-by-step explanation:

5 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago