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3 years ago

ANSWER NUMBER 5. SHOW YOUR WORK TOO PLZ!!!!!!

Mathematics

2 answers:

slamgirl [31]3 years ago

5 0

The correct answer is number line B.

Explanation:

We are given the inequality x >= -7, that means we have to represent on a number line all numbers that are greater than -7, including -7. that is correctly represented on the number line B, because the black full dot means that -7 is included and the direction of the line goes in the way which is greater than -7.

Hope this helps!

Usimov [2.4K]3 years ago

4 0

Well first youll have to flip the equation so i'll be x ≥ −7

On the graph you would start at point -7. Since it's greater or equal to sign the dot would be solid following the line to the right of the graph

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Eva is working two summer jobs, making $16 per hour tutoring and $8 per hour clearing tables. Last week Eva worked 3 times as ma

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Answer:

48 and 32 6 hours clearing tables and 2 hours tutoring

Step-by-step explanation:

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3 years ago

Greg has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Greg's Jumble has 6 clas

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4 years ago

Read 2 more answers

Expand 3(z+3) please help me solve this

mojhsa [17]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

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