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Colt1911 [192]
3 years ago
8

ONLY GODS CAN SOLVE STRAIGHT AWAY: Using the given equation find the missing coordinates of the points and then find the slope o

f the line.
4x−3y=24; A(...; 12), B(6; ...)



Erik took a trip to see his friend Mike who lives 308 miles away. He left his place at 10 AM driving at 70 mph. In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. At what time will they meet?
SAT
1 answer:
Yakvenalex [24]3 years ago
5 0

Answer:

By the time Mike left his house at 12:00 noon, Erik had already traveled: 2 x 70 mph =140 miles.

308 - 140 = 168 miles left.

Let the time when they meet =T

70T + 50T =168 miles, solve for T

T =7 / 5 =1.4 hours, or 1 hour and 24 minutes after 12:00 noon.

12 + 1.4 =1 O'clock + 24 minutes, or 24 minutes after 1:00 pm when they will meet.

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andreev551 [17]

The values of k and b of this graph that passes through the given points is k = \frac{20}{9}  and b = \frac{-50}{9}

<u>Given the following points:</u>

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To find the values of k and b since the graph passes through the given points:

First of all, we would determine the slope of the graph passing through the given points.

Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}

Substituting the points into the formula, we have;

Slope. \;m  = \frac{-10 - 10}{-7 - 2}\\\\Slope. \;m  = \frac{-20}{-9}\\\\Slope. \;m  = \frac{20}{9}

The standard form of an equation of line is given by the formula;

y = mx + b   ....equation 2

<u>Where:</u>

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Next, we would determine the intercept of the graph:

10 = \frac{20}{9}(2) + b\\\\10 =  \frac{40}{9} + b\\\\b =  \frac{40}{9} - 10\\\\b = \frac{40\; - \;90}{9}\\\\b = \frac{-50}{9}

The standard form of this equation of line is:

y = \frac{20}{9}x - \frac{50}{9}    .....equation 3.

Comparing eqn 1 and eqn 3, we can deduce:

k = \frac{20}{9}  and b = \frac{-50}{9}

Therefore, the values of k and b of this graph that passes through the given points is k = \frac{20}{9}  and b = \frac{-50}{9}

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Explanation


Explanation
Detail ste
Apply \(a^3\pm b^3=(a\pm b)(a^2\ mp ab+b^2)V : \((y + 3) (y^[2} - y \times 3 + 3^{2}) V
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The value of x for the given equation (x + 50)/2 = 13x is 2.

According to the given question.

We have an equation (x + 50)/2 = 13x, which represents  when two tutoring services with different rate plans charge the same fees for a session of x hours.

So, we have to solve the given equation (x + 50)/2 = 13x  for x.

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Hence, the value of x for the given equation (x + 50)/2 = 13x is 2.

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