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musickatia [10]
3 years ago
7

Which of the following is NOT a solution to the inequality graphed below?  

Mathematics
1 answer:
podryga [215]3 years ago
4 0
 i think the answer is  (0,-3)
You might be interested in
Cha
attashe74 [19]

Answer:

3.1%

Step-by-step explanation:

6/196 × 100% = 3.1%

8 0
3 years ago
I need help with box and whisker plots ASAP
bonufazy [111]
Box and whiskers plots use five number summaries. The first number is:
1:Minimum
2.Quartile 1
3.Mean
4.Quartile 2
5.maximum

Quartile are simple to get.
If your set of numbers is:
2,3,3,6,8,8,11
Then find the mean
2 3 3 |6| 8 8 11
Find the mean of the left side of of mean.
2 |3| 3 3 =Quartile 1
Then the right side
8 |8| 11 8 =Quartile 2
-----------------------------------------------
Your 5 number summary is 2,3,6,8,11
Plot them on the number line, but put a line above where the dot would go. take the 3 middle lines and connect to make a box. The lines on the outside of the box are the whiskers, AKA distributed data.
8 0
3 years ago
A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

                                                             = \frac{2}{7} tank of gas

Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
The price of a mat is x USD from the start. Write an expression for the price:
Serga [27]

Answer:

Hello good evening friend

5 0
2 years ago
4(-9x + 1) =<br> Answer?
faltersainse [42]

Answer:

−36+4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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