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3 years ago

How many times does 50,000 go into 374,000,000,000?

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

8 0

So you need to divide 374000000000 by 50,000 and you get 7480000

Mekhanik [1.2K]3 years ago

3 0

An easy way to do this problem is to make it smaller by canceling out matching zeros. 3740000/5 = 7,480,000

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The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC

DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x² ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)² ⇒(2)

Equating (1) and (2)

∴ 10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴ 10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0

3 years ago

4(1 – x) + 2 x = -3( x + 1)

Rashid [163]

Answer:

Step 1: Simplify both sides of the equation.

4(1−x)+2x=−3(x+1)

(4)(1)+(4)(−x)+2x=(−3)(x)+(−3)(1)(Distribute)

4+−4x+2x=−3x+−3

(−4x+2x)+(4)=−3x−3(Combine Like Terms)

−2x+4=−3x−3

Step 2: Add 3x to both sides.

−2x+4+3x=−3x−3+3x

x+4=−3

Step 3: Subtract 4 from both sides.

x+4−4=−3−4

x=−7

Step-by-step explanation:

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8 0

3 years ago

If Johnny has 4 apples and heather has 6 apples, how many apples will they have together?

sergejj [24]

Answer:

-2

Step-by-step explanation:

4 0

4 years ago

According to a recent survey of adults, approximately 62% carry cash on a regular basis. The adults were also

pochemuha

According to the probabilities given, it is found that the correct option regarding the independence of the events is given by:

No, P(carry cash) != P(carry cash|have children).

<h3>What is the probability of independent events?</h3>

If two events, A and B, are independent, we have that:

$P(A \cap B) = P(A)P(B)$

Which also means that:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

In this problem, we have that:

62% carry cash on a regular basis, hence P(cash) = 0.62.

46% has children, hence P(children) = 0.46.

Of the 46% who have children, 85% carry cash on a regular basis, hence P(cash|children) = 0.85.

Since P(carry cash) != P(carry cash|have children), they are not independent.

More can be learned about the probability of independent events at brainly.com/question/25715148

6 0

2 years ago

I’m I correct or no please help asap

GrogVix [38]

-sin X
4x cos x -4 sin x

<h2>hope it helps!</h2>

7 0

3 years ago