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4 years ago

PLEASE ANSWER ASAP 20 POINTS

Mathematics

1 answer:

Schach [20]4 years ago

6 0

X=7. The two segments on the bottom as well as on the diagonal are the same length. This shows that the entire triangle and the inner triangle on the right are similar. So if we call the length of the bottom 2y, then 84/2y=6x/y. Solving this we get 84=12x, and so x=7

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!!!WILL GIVE BRANLIEST ASAP!!!

posledela

Answer:

Domain: (-3,-3,0,4)

Range: (-5,0,1,7)

Function: No

Step-by-step explanation:

Because there is a repeating -3 in the domain.

Brainliest please!

6 0

4 years ago

Find the value of x in x + y= 9 and x - y= 3. 6 -6 3 -3

olga2289 [7]

x + y= 9 and x - y= 3

rearrange the second equation:

x - y= 3

x = 3 + y

x -3 = y

substitute y with "x-3" in the first equation and solve

x + y= 9

x + (x-3)= 9

2x -3 = 9

2x = 12

x = 6

you could also start with the first equation and substitute y in the second.

graphically speaking, it's the intersection point of to lines, at least the six-part of the point.

4 0

3 years ago

Copy and write the missing factor https://ibb.co/gAKUJA

alexira [117]

I think that the answer would be 5/5

4 0

3 years ago

Ms. Figgs asked 25 students in her 7th grade homeroom to select their favorite cookie. The results are recorded in the table bel

iren [92.7K]

Answer:

120

Step-by-step explanation:

3 0

3 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

earnstyle [38]

Answer:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

Step-by-step explanation:

Data given

$n_1 =10$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =1085$ represent the sample mean for the group 1

$\bar X_2 =1034$ represent the sample mean for the group 2

$s_1=52$ represent the sample standard deviation for group 1

$s_2=61$ represent the sample standard deviation for group 2

We are assuming that the two samples are normally distributed with equal variances and that means:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

System of hypothesis

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The degrees of freedom are given by:

$n_1+n_2 -2$

And the pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$S^2_p =\frac{(10-1)(52)^2 +(15 -1)(61)^2}{10 +15 -2}=3323.043$

And the deviation would be:

$S_p=57.646$

The degrees of freedom are:

$df=10+15-2=23$

The statistic would be:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

The p value would be

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

6 0

3 years ago