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Andreyy89
3 years ago
13

What was the history of technology since the 1980s to now and how is it used in classrooms?.?. PLEASE HELP

Computers and Technology
1 answer:
levacccp [35]3 years ago
3 0

Answer:

Please check the explanation.

Explanation:

The US education department mentioned that in 1900 there were only 10% of students enrolled in the schools, however by the end of 1992, the percentage increased by 85% and it became 95%. In 1930 1 million students were enrolled in university. And by 2012, it became 21.6 million. The teachers began to follow a new type of teaching, and the academics began to follow a special method for communique, education as well as for helping the students understand the concepts.

Though, after the 1980s the personal computer came into being in schools and colleges. Since then numerous versions of PC have originated in the marketplace as well as mobiles tracked by Smartphones, and now nearly 100% of people in the US have smartphones. Virtual reality, augmented reality, AI, Machine learning. etc. has cemented the way for the virtual classrooms. Also, each subject is now up with fruits and not just-food. The consequence is such a delightful setup of the Virtual schoolrooms in the entire US, and all over the ecosphere. The projectors, VR devices, AI applications for education, online classroom facility, Electronic version of chalkboards, and in fact everything is no sophisticated, and it is making not only teaching easy but learning as well. And the result is, students are ending up with better results, and teachers seem to be happier and more relaxed. And that is making school management satisfied as well.

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LAB: Parsing dates Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1,
Vladimir [108]

The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:

<h3>Python code</h3>

import datetime

inputs = []

result = []

#read the inputs

date = input()

inputs.append(date)

while not date == "-1":

 date = input()

 inputs.append(date)

#check if the input is in the correct format and convert it.

for date_text in inputs:

 try:

   date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")

   result.append(date_text.strftime("%d/%m/%Y"))

 except ValueError:

   pass

   

print(*result, sep = "\n")

The above code would parse the string and extract the date. The split() method was used to break the input into tokens.

Read more about python programming here:

brainly.com/question/27666303

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6 0
2 years ago
write a c++ program that reads from the user a positive integer (in a decimal representation), and prints its binary (base 2) re
Vesna [10]

Answer:

The program to this question can be described as follows:

Program:

#include <iostream> //defining header file

using namespace std;

int main() //defining main method

{

int x1,rem,i=1; //defining integer variable

long Num=0;// defining long variable

cout << "Input a decimal number: "; // print message

cin >> x1; //input value by user

while (x1!=0) //loop for calculate binary number

{

//calculating binary value    

rem= x1%2;

x1=x1/2;

Num =Num +rem*i;//holding calculate value

i=i*10;

}

cout <<Num;//print value

return 0;

}

Output:

Input a decimal number: 76

1001100

Explanation:

In the above code, four variable "x1, rem, i, and Num" is declared, in which three "x1, rem, and i" is an integer variable, and one "Num" is a long variable.

  • In the x1 variable, we take input by the user and use the while loop to calculate its binary number.
  • In the loop, first, we check x1 variable value is not equal to 0, inside we calculate it binary number that store in long "Num" variable, after calculating its binary number the print method "cout" is used to prints its value.  
5 0
3 years ago
What is the argument in this function =AVERAGE(F3:F26)
monitta
The argument for the function would be answer "D".
5 0
2 years ago
In the context of intentional security threats, _____ can erase data and wreak havoc on computers and networks but do not replic
mihalych1998 [28]

Answer:

The answer is "Option D".

Explanation:

Trojan program is a malicious code that is also known as a virus. It is a rootkit, that aims to infect the computer to hide or obscure an object. These programs are mainly used to download additional content, such as additional pieces of malware, to the infected computer, and other options are wrong that can be defined as follows:

  • In option A, It is not correct, this option infects the system.
  • In option B, It is used for infects another computer that's why it is incorrect.
  • In option C, It is incorrect because it is used in cybersecurity.  
5 0
3 years ago
g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
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