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3 years ago

What was the history of technology since the 1980s to now and how is it used in classrooms?.?. PLEASE HELP

Computers and Technology

1 answer:

levacccp [35]3 years ago

3 0

Answer:

Please check the explanation.

Explanation:

The US education department mentioned that in 1900 there were only 10% of students enrolled in the schools, however by the end of 1992, the percentage increased by 85% and it became 95%. In 1930 1 million students were enrolled in university. And by 2012, it became 21.6 million. The teachers began to follow a new type of teaching, and the academics began to follow a special method for communique, education as well as for helping the students understand the concepts.

Though, after the 1980s the personal computer came into being in schools and colleges. Since then numerous versions of PC have originated in the marketplace as well as mobiles tracked by Smartphones, and now nearly 100% of people in the US have smartphones. Virtual reality, augmented reality, AI, Machine learning. etc. has cemented the way for the virtual classrooms. Also, each subject is now up with fruits and not just-food. The consequence is such a delightful setup of the Virtual schoolrooms in the entire US, and all over the ecosphere. The projectors, VR devices, AI applications for education, online classroom facility, Electronic version of chalkboards, and in fact everything is no sophisticated, and it is making not only teaching easy but learning as well. And the result is, students are ending up with better results, and teachers seem to be happier and more relaxed. And that is making school management satisfied as well.

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Mary from sales is asking about the plan to implement Salesforce.com's application. You explain to her that you are in the proce

NARA [144]

Answer:

The correct answer to the following question will be Option b ( IT infrastructure).

Explanation:

This refers to either the integrated devices, applications, network infrastructure, as well as facilities needed by an organization This system to function, run, and maintain.

Your technology infrastructure seems to be the nervous system, which is accountable for supplying end customers with a streamlined operation.
Total control of both your operating system infrastructure ensures you can guarantee the channel's safety is tracked.

Therefore, it will be a part of the design of Mary.

7 0

3 years ago

Which types of attacks are thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and spe

lesantik [10]

The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

What is Brute Force Attacks?

This is known to be an attack that is said to be a very crude type of attack and it is often seen as a brute-force attack.

Note that is one that does not depend on lists of passwords, but it is one that often tries all the very possible combinations of permitted character types.

Hence, this type of attack was known to be historically seen as ineffective, and it is said to be The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

Learn more about Brute Force Attacks from

brainly.com/question/17277433

#SPJ1

3 0

2 years ago

Chegg Suppose the heap is a full tree, size 2^n-1. what is the minimum number of steps to change a min heap to a max heap. Show

adoni [48]

Answer:

Explanation:

We start from the bottom-most and rightmost internal node of min Heap and then heapify all internal modes in the bottom-up way to build the Max heap.

To build a heap, the following algorithm is implemented for any input array.

BUILD-HEAP(A)

heapsize := size(A)

for i := floor(heapsize/2) downto 1

do HEAPIFY(A, i)

end for

Convert the given array of elements into an almost complete binary tree.

Ensure that the tree is a max heap.

Check that every non-leaf node contains a greater or equal value element than its child nodes.

If there exists any node that does not satisfy the ordering property of max heap, swap the elements.

Start checking from a non-leaf node with the highest index (bottom to top and right to left).

4 0

2 years ago

Convert the following four unsigned binary numbers to decimal and show your work:

Ber [7]

Answer:

23 ,21,10,63,13

Explanation:

We have to convert binary to decimal

10111 corresponding decimal number is

$1\times 2^4+0\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=23$

10101 corresponding decimal number is

$1\times 2^4+0\times 2^3+1\times 2^2+0\times 2^1+1\times 2^0==21$

01010 corresponding decimal number is

$0\times 2^4+1\times 2^3+0\times 2^2+1\times 2^1+0\times 2^0=10$

111111 corresponding decimal number is

$1\times 2^5+1\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=63$

001111 corresponding decimal number is

$0\times 2^5+0\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=13$

7 0

3 years ago

Write a MIPS assembly language program that accomplishes the following tasks:The program will prompt the user to enter an intege

Svetlanka [38]

Answer:

Here's the code below

Explanation:

# All the comment will start with #

# MIPS is assembly language program.

# we store the all the data inside .data

.data:

k: .asciiz "Enter the kth value:\n"

.text

.globl main

li $s0, 0 # $s0 = 0

li $t0, 0 # $t0 = 0

la $n0, k # $n0 is kth value address

syscall # call print_string()

li $v0, 0 # $v0

syscall

move $n0, $v0 # $a0 = user input or "int n"

addi $sp, $sp, -4 # move the stack pointer down

sw $ra, 0 ($sp) # save the return address for main

jal fncheck # call fncheck(n);

fncheck:

beq $n, 0, fnfirst #if n==0 then fnfirst

ble $n0, 5, fnrec # if (n <=5) then 5

bge $n0, 5, fnjoke

#first function for n 0 and 1

fnfirst:

li $t0, 0 # initialize $t0 = 0

addi $t0, $t0, 20 # $t0 = 20

move $v0, $t0 # return 20

jr $ra

#function to execute 5*function1(n-2) + n;

fnrec:

sub $sp, $sp, 12 # store 3 registers

sw $ra, 0($sp) # $ra is the first register

sw $n0, 4($sp) # $n0 is the second register

addi $n0, $n0, -2 # $a0 = n - 2

jal function1

sw $v0, 8($sp) # store $v0, the 3rd register to be stored

lw $n0, 4($sp) # retrieve original value of n

lw $t0, 8($sp) # retrieve first function result (function1 (n-2))

mul $t0, $t0, 5 # $t0 = 5 * function1(n-2)

add $v0, $v0, $t0

lw $ra, 0($sp) # retrieve return address

addi $sp, $sp, 12

jr $ra

#function to print joke

fnjoke:

la "Joke section"

4 0

3 years ago