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Yuliya22 [10]
3 years ago
12

What is the decimal form of 100/3, 100/5, and100 /6?

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0
33.3
55.5
66.6
Are your answers
Alika [10]3 years ago
5 0

Answer:

100/3=33.3333

100/5=20.0

100/6=16.6666666667

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Hellpppppppppppppppp​
VLD [36.1K]

Answer:

15 cups

Step-by-step explanation:

5x3 is 15

even the denominator by multiplying.

do what you multiplied on the numerator.

4 0
3 years ago
Read 2 more answers
Five friends buy tickets to a carnival. They each also spend $4 on a funnel cake. They spent a total of $60. How much does one t
Butoxors [25]

Answer:

$8 for each tickets

Step-by-step explanation: 60/5 equals 12

Each friends have $12

12-4=8

Each ticked cost 8 dollars.

4 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
4 years ago
Question 13<br> HELPPP<br> Thanks
taurus [48]
Your answer is c ur welcome
4 0
2 years ago
Write the Slope-Intercept and Point-Slope forms of the line passing through the point (-3, 2) and having a slope of -4/5
weeeeeb [17]

Answer:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

Step-by-step explanation:

The slope-intercept form of a line is written as y = mx + b, where m is the slope and b is the y-intercept.

The point-slope form of a line is written as y - y1 = m(x - x1), where (x1, y1) is a given point and m is the slope.

Here, we see that the slope is -4/5, which means that m = -4/5. Since we're given a point (-3, 2), let's go ahead and just write the point-slope form already. (x1, y1) = (-3, 2) so x1 = -3 and y1 = 2. Then:

y - y1 = m(x - x1)

y - 2 = (-4/5) * (x + 3)

y-2=\frac{-4}{5} (x+3)

Now, we want to find the slope-intercept form, so we need to figure out the y-intercept. Well, first, let's plug in what we know:

y = mx + b

y = (-4/5)x + b

Any point on this line will satisfy the above equation. Since (-3, 2) is on this line, if we plug -3 in for x and 2 in for y, the equation should hold true, so we can solve for b:

y = (-4/5)x + b

2 = (-4/5) * (-3) + b

2 = 12/5 + b

b = -2/5

So, the y-intercept is -2/5. Then the slope-intercept form is:

y=\frac{-4}{5} x-\frac{2}{5}

Thus, our two equations are:

slope-intercept: y=\frac{-4}{5} x-\frac{2}{5}

point-slope: y-2=\frac{-4}{5} (x+3)

8 0
3 years ago
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