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Yuliya22 [10]
2 years ago
12

What is the decimal form of 100/3, 100/5, and100 /6?

Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0
33.3
55.5
66.6
Are your answers
Alika [10]2 years ago
5 0

Answer:

100/3=33.3333

100/5=20.0

100/6=16.6666666667

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Exercise
Maurinko [17]
X - nominator
y - denominator

\frac{3x}{y+12}=\frac{3}{4}\\
\frac{x+7}{3y}=\frac{1}{2}\\\\
3(y+12)=12x\\
2(x+7)=3y\\\\
3y+36=12x\\
2x+14=3y\\\\
2x+14+36=12x\\
10x=50\\
x=5\\\\
3y=2\cdot5+14\\
3y=10+14\\
3y=24\\
y=8\\\\
\frac{x}{y}=\boxed{\frac{5}{8}}
6 0
3 years ago
On an average day, a garden snail can travel about 0.05 mile. The snail travels 0.2 times as far as the average distance on day
daser333 [38]

Answer: 0.04 miles

 

SOLUTION

 

Given,

Average daily distance of a garden = 0.05 mile.

 

Distance traveled on day 1 = 0.2 times as far as the average distance

= 0.2 x 0.05 miles

= 0.01 miles

 

Distance traveled on day 2 = 0.6 times as far as the average distance

= 0.6 x 0.05 miles

= 0.03 miles

 

Total distance traveled in two days

= Distance traveled on day 1 + Distance traveled on day 2

= 0.01 miles + 0.03 miles

= 0.04 miles

6 0
3 years ago
A teacher surveyed her students about the amount of time the students
LiRa [457]

Answer:

c

Step-by-step explanation:

I just had the exact same question on a worksheet

5 0
3 years ago
In arithmetic sequence tn find: S10, if t2=5 and t8=15
makkiz [27]

Given:

\bold{t_2=5}\\\\\bold{t_8=15}\\\\

To find:

\bold{T_n=?}\\\\\bold{S_{10}=?}

Solution:

\to \bold{t_2=5}\\\\  \bold{a+d=5} \\\\  \bold{a=5-d} ................(i)\\\\ \to \bold{t_8=15}\\\\ \bold{a+ 7d=15}.................(ii)\\\\

Putting the equation (i) value into equation (ii):

\to \bold{5-d+7d=15}\\\\\to \bold{5+6d=15}\\\\\to \bold{6d=15-5}\\\\\to \bold{6d=10}\\\\\to \bold{d=\frac{10}{6}}\\\\\to \bold{d=\frac{5}{3}}\\\\

Putting the value of (d) into equation (i):

\to \bold{a=5-\frac{5}{3}}\\\\\to \bold{a=\frac{15-5}{3}}\\\\\to \bold{a=\frac{10}{3}}\\\\

Calculating the \bold{t_n :}

\to \bold{t_n=a+(n-1)d}\\\\\to \bold{t_n=\frac{10}{3}+(n-1)\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}+\frac{5}{3}n-\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}-\frac{5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{10-5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{5}{3} +\frac{5}{3}n}\\\\ \to \bold{t_n=\frac{5}{3}(1+n)}\\\\

Formula:

\bold{S_n = \frac{n}{2}[2a + (n - 1)d ] }\\

Calculating the \bold{S_{10}} :

\to \bold{S_{10} = \frac{10}{2}[2\frac{10}{3} + (10- 1)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + (9)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 9 \times \frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 3\times 5 ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 15 ] }\\\\\to \bold{S_{10} = 5[\frac{20+ 45}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{65}{3} ] }\\\\\to \bold{S_{10} = 5 \times \frac{65}{3}  }\\\\\to \bold{S_{10} =  \frac{325}{3}  }\\\\\to \bold{S_{10} =108.33 }

Therefore, the final answer is  " \bold{\frac{5}{3}(1+n)\ and\ 108.33}"

Learn more:

brainly.com/question/11853909

7 0
3 years ago
Select all that justify the following statement.
Kay [80]
This one 10 + x12 = 12x + 10 is <span>a) commutative - addition
And this </span>10 + x12 =10 + 12x is <span>e) commutative - multiplication

So you use them both. And they're both correct. </span>
6 0
3 years ago
Read 2 more answers
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