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Alex
4 years ago
12

Consider the following multiple regression model

Mathematics
1 answer:
-Dominant- [34]4 years ago
4 0

Answer:

We fail to reject the null hypothesis only if either estimated? coefficient, Modifying Above beta with caret 1?1 or Modifying Above beta with caret 2?2?, is precisely equal to zero is correct option.

You might be interested in
Simplify (5 x + 1) - (-10 x + 6)
tekilochka [14]

Answer:15x+7

Step-by-step explanation:

First you would see that the -(-10x+6) would turn into 10x+6 meaning that the whole equation would turn into 5x+1+10x+6. Then add the x numbers together and the whole numbers separate. So now your answer should be 15x+7

8 0
3 years ago
Read 2 more answers
I don’t kno the answer help
PolarNik [594]

Answer:

Yes

Step-by-step explanation:

It is true because the equation would be 1 is less than or equal to 3-(-4)

4 0
3 years ago
A recipe calls for 1 3/4 cups of flour. If the recipe is tripled, how much flour is needed?
Grace [21]
3 and 9/12 you can simplify it still, you figure that part out ;)<span />
7 0
3 years ago
One-fourth of a number is five-eighths. Find the number.
ioda

Answer:

5/32

Step-by-step explanation:

Since 5/8 x 1/4 = 5/32, that is the answer.

Key Note: When you get this type of question, multiply the second  umber by the first.

4 0
4 years ago
Describe the region enclosed by the circle x^2 +y^2 = 11x in polar coordinates.
vivado [14]

Answer:

the region of the circle in polar coordinate can be expressed as:

\mathbf{- \dfrac{\pi}{2} \leq \theta \leq \dfrac{\pi}{2} , 0 \leq r \leq 11 cos \theta}

Step-by-step explanation:

Given that:

x^2 +y^2 = 11x

This implies that :

(x-5.5)^2 + y^2 = 5.5^2

center (5.5, 0) and radius = 5.5

The relation between the cartesian coordinates (x,y) and the polar coordinates (r, θ) is as follows:

x = rcosθ

y = rsinθ

Thus, x^2 + y^2 = r^2

x^2 + y^2 = 11x

(rcos \theta)^2 + (r sin \theta)^2 = 11(rcos \theta)

r^2 = 11r cos \theta

Thus, the angle θ runs between - \dfrac{\pi}{2} to \dfrac{\pi}{2}

Therefore, the region of the circle in polar coordinate can be expressed as:

\mathbf{- \dfrac{\pi}{2} \leq \theta \leq \dfrac{\pi}{2} , 0 \leq r \leq 11 cos \theta}

7 0
4 years ago
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