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riadik2000 [5.3K]
4 years ago
15

40% of a nurse time is spent disowning medicine to patients. if 16 hours is spent dispensing medicine, how many hours does the n

urse work
Mathematics
2 answers:
Ber [7]4 years ago
4 0
40 % = 16 hours
100 % = 40 hours, the nurse works for 40 hours.
this can be proven by 40% of 40 is 16.
loris [4]4 years ago
3 0
0.40x = 16
X= 16/0.40
X = 40
She worked 40 hours
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A flowerbed is to be 3m longer than its width.the flowerbed will have an area of 70m²​
melomori [17]
ANSWER
Yes, it is a quadratic equation which is x² + 3x - 70 = 0

SOLUTION

Area = Length × Width
Let x be the Length, L = x
Length is 3 cm longer than its width, thus, W = x + 3
The Area is equal to 70m², thus, A = 70m²

In Mathematical representation,
A = L × W
70 = (x)(x + 3)
70 = x(x) + x(3)
70 = x² + 3x
0 = x² + 3x - 70
4 0
3 years ago
A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2
AVprozaik [17]
Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.
7 0
3 years ago
A recipe calls for 2 1/2 cups flour, 3/4 cups of sugar and 2 eggs. How much of each ingredient do you need to make half the reci
wariber [46]
You would need 5/4 cups of flour, 3/8 cups of sugar and 1 egg to make half of the recipe.
4 0
3 years ago
This trapezoid has been divided into two right triangles and a rectangle.
Travka [436]

Answer:

Step-by-step explanation:

the area of the rectangle 168 / the triangle on the left is 12/also the triangle on the right is 12/the area of the trapezoid is 192

8 0
2 years ago
A potato was launched in the air using a potato gun. The function for the situation was h(t)=-16t^2 +100t+10, where t was the ti
Goshia [24]

Answer:

The height equation is:

h(t)=-16t^2 +100t+10

A) To find the maximum height, we must find the time where the velocity is 0, so we must derive it with respect to the time.

v(t) = -2*16*t + 100 = 0

       t = 100/(2*16) = 3.125s

Now we put this time in our height equation:

h(3.125s) = -16*3.125^2 + 100*3.125 + 10 = 166.25 ft.

B) The lowest heigth of the potato will be h = 0ft, when the potato hits the ground.

C) the lowest time that works for that function is t = 0s, when the potato is fired by the gun.

D) the maximum time can be finded when the potato hits the ground, afther that point the equation does not work anymore, let's find it,

h(t) = 0 = -16t^2 +100t+10

we can solve it using Bhaskara's equation:

t = \frac{-100 +- \sqrt{100^2 +4*16*10} }{-2*16} = \frac{-100 +- 103.2}{-32}

So the two solutions are:

t = 6.3s

t = -0.1s

We need to chose the positive time, as we already discused that the minimum time that works for the equation is t = 0s.

so here the answer is t = 6.3s

E) the domain is  0s ≤ t ≤ 6.3s

The range is 0ft ≤ h ≤ 166.25 ft.

4 0
3 years ago
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