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cupoosta [38]
3 years ago
10

show me a picture of 712÷8in long division form plz help me and show me pictures it's due and it's really hard please help me an

d I'll help you guys whoever answers first
Mathematics
2 answers:
icang [17]3 years ago
8 0
712/8=? First found out what 71/8 is. 71/8 is 8 and 7/8. This tells that there is 7 left so now you add 7 to two which gives you 72. Then you divide 72/8=9 and combine 8 and 9 which gives you 89. So 712/8=89
Lostsunrise [7]3 years ago
4 0
Show me a picture of 712÷8in long division form plz help me and show me pictures im 5 years old
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At the start of an experiment, the temperature of a solution was -12°C. During the expirament
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Answer:

The final temperature of the solution was 5°C

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3 0
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Read 2 more answers
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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
3 years ago
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