Question

one number is 1 more than 2 times another. if their sum is increased by sevan, the result is twenty six

Answer 1

the numbers are 6 and 13

let x be one of the numbers then the other is 2x + 1

their sum increased by 7 = 26

x + 2x + 1 + 7 = 26

3x + 8 = 26

subtract 8 from both sides

3x = 26 - 8 = 18

divide both sides by 3

x = $\frac{18}{3}$ = 6

the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13