Answer:
31 bits.
Explanation:
Given, total number of registers = 55
Total instructions = 60
Size of memory = 16 KB
Now, no of registers are 55. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a register operand.
Number of instructions = 60. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a instruction.
Size of memory = 64 KB = 26 * 210 * 23 bits = 219 bits. Hence, 19 bits are required to represent a memory location.
Now, an instruction has 2 parts, opcode and operand. As given there are only two address instructions which are memory operand and register operand.
Hence, total bits would be: 6 bits (opcode) + 6 bits (register operand) + 19 (memory operand) = 31 bits.
Answer and Explanation:
First of all we should have to know about PMT
PMT
stands for payment .payment that you want to send and receive.It is used in financial calculators and equation. It is a payment that return the periodic payment for a loan.
From the given statement we have to calculate the PMT for this purpose .
let us consider example where we take loan amount and have some interest and then calculate it.
loan of amount = $6000.00
Interest rate = 4.20%
period per year=15
period = 60
then monthly payment = $ 111.40
Using Excel then we get the monthly payment in cell C9
as calculations has been shown in the excel.
where you can get function who returns a positive value.
C. database administrators are responsible for organizing a company's data making sure all the data is accurate' available' and secure
Answer:
Here are the for loop for the given question.
for (i = 0; i < NUM_VALS; i++) // for loop
{
/* check if the value of i is equal to NUM_VALS or not.If it is
equal then just print the value without comma.*/
if(i==(NUM_VALS-1)) // if block
System.out.print(hourlyTemp[i]);
/* if i is not equal then just print the value with comma.*/
else // else block
System.out.print(hourlyTemp[i] + ", ");
}
Explanation:
In this we iterating the for loop and check the condition
check if the value of i is equal to NUM_VALS or not.If it is equal then just print the value without comma
If i is not equal then just print the value with comma .
Output:
90,92,94,95
The code range is <span>
10021-19499</span>
Procedures on the integumentary system
have their codes that range within 10021 – 19499 of the CPT manual. This is the
1st subsection of surgery. You will find codes for skin tag removal,
incisions, and wound debridement at the front of the integumentary system.