Answer:
Option (4) is correct about BQ
Step-by-step explanation:
Given : From the figure : ∠BQA = 54° and ∠BAQ = 36°
Now, Since ∠BAQ = 36° > 30°
So, ∠BAQ is not acute.
⇒ (1) is rejected.
Also, ∠BQA = 54° > 30°
So, ∠BQA is not acute.
⇒ (2) is rejected.
Now, in ΔABQ, By using angle sum property of a triangle
∠BAQ + ∠BQA + ∠ABQ = 180°
⇒ 36° + 54° + ∠ABQ = 180°
⇒ ∠ABQ = 90°
Since, ∠ABQ is right angle so, (3) is rejected.
Now, ∠ABQ = 90° and the line which is exterior to the circle and makes right angle with the radius of the circle is always tangent to the circle.
Hence, Option (4) is correct about BQ.
Therefore, BQ is a tangent line because m∠ABQ = 90°
Answer:
The answer your looking for is (0,64) because your asking what is the vertex form. If you need any other help with any questions let me know and I'lll be happy to help you
Step-by-step explanation:
Answer:
x = −6
Explanation:
5x + 7y = -23
Y = -2x - 11
Substitute -2x - 11 for y in 5x + 7y = -23
5x + 7(−2x − 11) = −23
Simplify both sides of the equation
5x + 7(−2x − 11) = −23
5x + (7)(−2x ) + (7)(−11) = −23 (Distribute)
5x + −14x + −77 = −23
(5x + −14x) + (−77) = −23 (Combine Like Terms)
−9x + −77 = −23
−9x − 77 = −23
Add 77 to both sides
−9x − 77 + 77 = −23 + 77
−9x = 54
Divide both sides by -9
−9x / -9 = 54 / -9
x = -6
