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Nutka1998 [239]
4 years ago
13

What is 3.313 Rounded to the nearest tenth

Mathematics
2 answers:
I am Lyosha [343]4 years ago
4 0
3.310 because your rounding the tenths so 3 isn't big enough to add to to the tenths too its 3.310
Lady_Fox [76]4 years ago
3 0
3.313 rounded to the nearest tenth is 3.3

hope this helps
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Answer:

8

Step-by-step explanation:

DCB and ABC are right angles

DCB = 90 = 7x + 34

If 7x + 34 = 90, then 7x = 56 and x = 8

Hope this helps :)

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Step-by-step explanation:

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3 years ago
Perimeter the coordinates of the vertices of a quadrilateral are R(-1,3), S(3,3), T(5,-1), and U(-2,-1)
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Answer:

The perimeter is equal to P=(11+2\sqrt{5}+\sqrt{17})\ units  or P=19.59\ units

Step-by-step explanation:

we have

The coordinates of the vertices are

R(-1,3), S(3,3), T(5,-1), and U(-2,-1)

plot the figure to better understand the problem

see the attached figure

we know that

The perimeter of a quadrilateral is the sum of its four length sides

so

P=RS+ST+TU+UR

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance RS

R(-1,3)\\S(3,3)  

substitute the values

d=\sqrt{(3-3)^{2}+(3+1)^{2}}

d=\sqrt{(0)^{2}+(4)^{2}}

RS=4\ units

step 2

Find the distance ST  

S(3,3)\\T(5,-1)  

substitute the values

d=\sqrt{(-1-3)^{2}+(5-3)^{2}}

d=\sqrt{(-4)^{2}+(2)^{2}}

ST=2\sqrt{5}\ units

step 3

Find the distance TU

T(5,-1)\\U(-2,-1)  

substitute the values

d=\sqrt{(-1+1)^{2}+(-2-5)^{2}}

d=\sqrt{(0)^{2}+(-7)^{2}}

TU=7\ units

step 4

Find the distance UR  

U(-2,-1)\\R(-1,3)  

substitute the values

d=\sqrt{(3+1)^{2}+(-1+2)^{2}}

d=\sqrt{(4)^{2}+(1)^{2}}

UR=\sqrt{17}\ units

step 5

Find the perimeter

P=RS+ST+TU+UR

substitute the values

P=4+2\sqrt{5}+7+\sqrt{17}

P=(11+2\sqrt{5}+\sqrt{17})\ units -----> exact value

P=(11+4.47+4.12)=19.59\ units -----> approximate value

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3 years ago
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o-na [289]

Answer:

idk

Step-by-step explanation:

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3 years ago
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