All categories

3 years ago

Write The decimal as a percent .065

Mathematics

2 answers:

Alenkasestr [34]3 years ago

8 0

The decimal as a percentage will look like 6.5%

grigory [225]3 years ago

5 0

Answer:

6.5

Step-by-step explanation:

You might be interested in

If f(X+4) =3x+4 , then find the value of f(4) <br>please explain it clearly .

Paul [167]

$\\ \sf\longmapsto f(x+4)=3x+4$

$\\ \sf\longmapsto f(x)=3x+4-4$

$\\ \sf\longmapsto f(x)=3x$

Now

$\\ \sf\longmapsto f(4)$

$\\ \sf\longmapsto 3(4)$

$\\ \sf\longmapsto 12$

7 0

3 years ago

Help me please can anyone figure this out this is due soon also make sure there an explanation.

Anvisha [2.4K]

Answer:

Watch a photo!

3 0

3 years ago

What is 2/3 minus 1/5 equals? Steps I need to show.

notka56 [123]

Firstly we need to find the common denominator:

2/3 - 1/5 =
= 10/15 - 3/15 =
= 7/15

We can't simplify it so that's the result :) I hope it will help you :)

4 0

3 years ago

Read 2 more answers

Makenzie is looking to purchase a used Jeep Wrangler that costs $21,000. She will make a $4,000 down payment and borrow the rema

olga_2 [115]

Answer:

$323

Step-by-step explanation:

The monthly payment can be calculated using the formula:

$M=\frac{P(\frac{r}{12})(1+\frac{r}{12})^n}{(1+\frac{1}{12})^n-1}\\\\$

where:

M=monthly payment
P=amount borrowed
r=annual interest rate
n=total number of monthly payments:

Our parameters are defined as:

$n=60\\P=21000-4000=17000\\r=5.3%\\\\$

We plug our parameters in the equation to solve for M;

$M=M=\frac{P(\frac{0.053}{12})(1+\frac{0.053}{12})^n}{(1+\frac{0.053}{12})^{60}-1}\\\\\\\\$

$=\frac{P(\frac{0.053}{12})(1+\frac{0.053}{12})^{60}}{(1+\frac{0.053}{12})^{60}-1}\\\\\\=323.15$

$=323.15\approx\$323$

Hence, the monthly payment is $323

8 0

4 years ago

Harper has $15to spend at the grocery store.She is going to buy bags of fruit that cost $4.75 each and one box of crackers that

Yuki888 [10]

Answer:

The maximum number of fruits bag Harper can buy are 3.

Step-by-step explanation:

Let there be x bags of fruits.

Let there be y boxes of chocolates

Cost of 1 bag of fruit = $4.75

So, cost of x bags = $4.75x

Cost of one box of crackers costs = $3.50

As per the given situation, the inequality forms:

$4.75x+3.50y\leq 15$

So, the maximum number of bags of fruit Harper can buy, is when she buys no box of cracker.

So, putting y = 0 in above inequality , we have,

$4.75x+3.50(0)\leq 15$

=> $4.75x+0\leq 15$

=> $4.75x \leq 15$

$x\leq 3.15$ rounding to 3.

Hence, the maximum number of fruits bag Harper can buy are 3.

5 0

3 years ago