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vfiekz [6]
3 years ago
8

You have screened for several new recessive mutations in a species of wasp. Wasps homozygous for apricot (aa) have pale orange e

yes. (Wild-type eyes are brown.) Wasps homozygous for blunt (bb) have short wings. (Wild-type wings are long.) You make a pure-breeding double-mutant (apricot, blunt) line and cross it with wild-type wasps. The F1 is wild-type in appearance. You testcross the F1 dihybrids with the double-mutant line (the “tester” genotype) and obtain four phenotypes in the F2: wild type apricot, blunt apricot blunt Determine the following for each F2 phenotype: the haploid genotype of the gamete it received from the F1 dihybrid its full diploid genotype whether the gamete it received from the F1 dihybrid was recombinant (REC) or nonrecombinant (nonREC). Complete the table by dragging the white labels to the gray targets, the blue labels to the blue targets, and the pink labels to the pink targets. Labels can be used once, more than once, or not at all. View Available Hint(s) ResetHelp ABGroup 1 AB AabbGroup 2 Aabb AbGroup 1 Ab aaBbGroup 2 aaBb aBGroup 1 aB aabbGroup 2 aabb abGroup 1 ab RECGroup 3 REC AaBbGroup 2 AaBb non RECGroup 3 non REC G1 G1 G1 G1 G2 G2 G2 G2 G3 G3

Biology
1 answer:
egoroff_w [7]3 years ago
6 0

A pure-breeding double-mutant (apricot, blunt) has aabb genotype, wild-type wasp has genotype AABB. If we cross them:

P: aabb  x  AABB

F1: all the genotypes would be AaBb

If we ten cross the F1 dihybrids with the double-mutant line:

AaBb  x  aabb

F2:  (table)

The four phenotypes are: 1) wild-type, 2) wild type apricot-short, 3) pale orange-wild type  blunt, 4) double-mutant.

The possible haploid genotypes of the gamete it received from the F1 dihybrid:  AB, Ab, aB, ab. AB and ab are nonrecombinant (nonREC), like those from parents, while Ab and aB gamets are recombinant (REC) .

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