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gogolik [260]
4 years ago
7

HELP ASAP FOR BRAINLIEST: The mean score for a standardized test is 1700 points. The results are normally distributed with a sta

ndard deviation of 75 points. What is the probability that a student will score more than 1700 points? Show work please :)
Mathematics
1 answer:
WITCHER [35]4 years ago
8 0

Answer:

Step-by-step explanation:

Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = test reults

µ = mean score

σ = standard deviation

From the information given,

µ = 1700 points

σ = 75 points

We want to the probability that a student will score more than 1700 points. This is expressed as

P(x > 1700) = 1 - P(x ≤ 1700)

For x = 1700,

z = (1700 - 1700)/75 = 0/75 = 0

Looking at the normal distribution table, the probability corresponding to the z score is 0.5

P(x > 1700) = 1 - 0.5 = 0.5

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iren2701 [21]

Answer:

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That's why you are getting wrong answer or you are not getting 7 in your calculator

8 0
3 years ago
A department store buys a necklace for $65 and uses a markup rate of 45%. whats the selling price?
Veronika [31]
Multiply 65 by .45 which is 29.25, and you add it to 65 since it says “markup” in the problem. So the answer is $94.25
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3 years ago
In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg
siniylev [52]

Answer:

\dfrac{AP}{PC}=\dfrac{3}{5}

\dfrac{BN}{CN}=\dfrac{3}{5}

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

  • angle A is the common angle, so \angle MAP\cong \angle DAC by reflexive property;
  • angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

so

\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}

Consider triangles ACB and PCN. In these triangles,

  • angle C is the common angle, so \angle ACB\cong \angle PCN by reflexive property;
  • angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,

so

\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

4 0
3 years ago
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Dmitry_Shevchenko [17]

Answer:

A

Step-by-step explanation:

153.03 = 2.85h + 73.23

2.85h = 153.03 - 73.23

2.85h = 79.8

h = 79.8 ÷ 2.85

h = 28

6 0
3 years ago
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Last year, there was 213 pies baked for a bake sale. This year, there were k pies baked. Using k, write an expression for the to
mylen [45]
To get the total number of pies baked in two years you need to add the total number of pies baked each of those years so the answer is: 213+k= total amount of pies baked in two years
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4 years ago
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