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max2010maxim [7]
3 years ago
15

What is the true solution to 2 ln e^ln5x=2 ln 15

Mathematics
2 answers:
fomenos3 years ago
6 0
First you should see that the 2s cancel out.  The equation becomes:

ln( e^{ln(5x)} ) = ln15

Use the laws of logarithms, knowing that ln(e) = 1.  

ln(5x) = ln(15)
 \\ 
5x = 15
 \\ 
x = 3

The answer is B.  

Hopefully this helps!


denis23 [38]3 years ago
6 0

Answer:

x=3

Step-by-step explanation:

Given in an equation as

2 ln e^ln5x=2 ln 15

Divide 2 to get

ln e^ln5x= ln 15

Using log rules for exponents we get

ln 5x = ln 15

Cancel ln to get

5x=15x=3

Hence solutin is x=3

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