Question

What is the true solution to 2 ln e^ln5x=2 ln 15

Answer 1

First you should see that the 2s cancel out.  The equation becomes:

$ln( e^{ln(5x)} ) = ln15$

Use the laws of logarithms, knowing that ln(e) = 1.  

$ln(5x) = ln(15) \\ 5x = 15 \\ x = 3$

The answer is B.  

Hopefully this helps!

Answer 2

Answer:

x=3

Step-by-step explanation:

Given in an equation as

$2 ln e^ln5x=2 ln 15$

Divide 2 to get

$ln e^ln5x= ln 15$

Using log rules for exponents we get

ln 5x = ln 15

Cancel ln to get

$5x=15x=3$

Hence solutin is x=3