Question

Help me solve those show work 3(2a-5)=12-7a, 27=3c-3(6-2c)and 6c-8-2c=-16

Answer 1

1) 3(2a-5)=12-7a

First distribute the 3. This leaves you with 6a-15=12-7a.

Now, add 15 to both sides. This leaves you with 6a=27-7a.

Now, add 7a to both sides. This leaves you with 13a=27.

Now, you can finally divide 13a on both sides. This leaves you with a=27/13

2) 27=3c-3(6-2c)

First, distribute the 3.This leaves you with 27=3c-18+6c

Now, combine like terms/simplify. This leaves you with 27=9c-18.

Now, add 18 to both sides. This leaves you with 45=9c.

Now, you can finally divide 9 on both sides. This leaves you with 5=c.

Lastly, use the reflexive property. This leaves you with c=5.

3) 6c-8-2c=-16

First, combine your like terms. This leaves you with 4c-8=-16.

Now, add 8 to both sides. This leaves you with 4c=-8.

Now, divide 4 on both sides. This leaves you with c=-8/4.

Finally, you can simplify the fraction. This leaves you with c=-2.

Comment if you have any questions!