1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.
x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta
Answer:
y = -2x - 10
Step-by-step explanation:
Slope intercept form of equation is of form
y = mx+c
where m is the slope of line and c is the y intercept of the line.
Y intercept is point on y axis where the line intersects the y axis.
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Given equation
y = -2x +4
comparing it with y = mx+ c
m = -2 , c = 4
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when two lines are parallel, their slopes are equal.
Let the equation of new line in slope intercept form be y = mx + c
Thus slope of of new required line is -2
Thus m for new line is -2.
now, equation of required line : y = -2x+c
Given that this line passes through (-4, -2). This point shall should satisfy equation y = -2x+c.
Substituting the value of (-4, -2) we have
-2 = -2(-4)+c
=> -2 = 8 +c
=> -2 -8 = c
=> c = -10.
Thus , equation of required line is y = -2x - 10.
Answer: 5 benches and 23 students
Step-by-step explanation:
I will answer in English.
We have E students and B benches.
If we sit 4 students per bench, we have 3 students left.
then:
E = 4*B + 3
And if we sit 5 students per bench, there are two places with no students sited.
E = 5*B - 2
now we can replace the E in the second equation with the right part in the first equation:
4*B + 3 = 5*B - 2
3 + 2 = 5*B - 4*B
5 = B
So we have 5 benches, and:
E = 4*5 + 3 = 23 students.
Answer:
Perimeter square = 8 sqrt(pi)
Step-by-step explanation:
The perimeter of a square is 4*s
The area of a circle is Area = pi * r^2
The circumference of a circle is C = 2*pi * r
C = 4 pi
4pi = 2*pi * r
r = 2
So the area of the circle is pi * r^2 = pi * 2^2 = 4pi
The square has the same area
Area = 4*pi
Square = 4*pi
s^2 = 4*pi
s = sqrt(4*pi)
s = 2*sqrt(pi)
The perimeter = 4 * 2 * sqrt(pi)
The perimeter = 8 * sqrt(pi)
