A room has an area of 60 square meters and a perimeter of 32 meters what are the length and width of the room
1 answer:
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Answer:
Larger number = 34
Smaller number = 17
Step-by-step explanation:
Given that:
Sum of numbers = 51
Let,
x be the larger number
y be the smaller number
According to given statement;
x+y=51 Eqn 1
x = 2y Eqn 2
Putting x=2y in Eqn 1
2y+y=51
3y=51
Dividing both sides by 3
Putting y=17 in Eqn 2
x=2(17)
x=34
Hence,
Larger number = 34
Smaller number = 17