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3 years ago

The distance around the school track is 1/4 Mile how many times around the track does Cheryl need to run in order to run 1 mile

Mathematics

2 answers:

Natali5045456 [20]3 years ago

8 0

Answer:

4 rounds

Step-by-step explanation:

Because the distance around the school track is 1/4 mile, to achieve 1 mile or can also be written as 4/4 mile, he will have to run in total of:

1 / 1/4

= 1*4/1

= 4 rounds

Hope this help you :3

Burka [1]3 years ago

4 0

Answer: She needs to run 4 times around the track in order to run 1 mile.

Step-by-step explanation:

You need to analize the information provided:

- Cheryl need to run 1 mile.

- The distance around the school track is $\frac{1}{4}$ mile.

Therefore, in order to calculate the number of times Cheryl needs to run around the school track, you need to divide 1 miles by $\frac{1}{4}$ mile.

Then, you get:

$\frac{1mi}{\frac{1}{4mi}}=4$

Therefore, she needs to run 4 times around the track in order to run 1 mile.

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3 years ago

Decomponha os seguintes números a) 1.585 = b) 1.059= c) 2.440 d) 5.329 e) 8.801 f) 9.999 g) 3.718 h) 6.840 i) 7.504 j) 5.225 1)

vlada-n [284]

Answer:

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

Step-by-step explanation:

A medida que nos alejamos del punto decimal, el número de ceros aumenta y el dígito se mueve hacia la derecha.

Los valores después del decimal se denominan décimas, centésimas y milésimas.

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

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