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VikaD [51]
3 years ago
15

2(3x+7)+x=70 That it I need help

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

2(3x+7)+x=70

mutiply the bracket by 2

(2)(3x)(2)(7)+x= 70

6x+14+x= 70

6x+x+14= 70 ( combine like terms)

7x+14= 70

move 14 to the other side

sign changes from +14 to -14

7x+14-14=70-14

7x= 56

divide both sides by 7

7x/7= 56/7

x=8

Answer: x= 8

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Please help!<br> "Congruence and Constructions".
marin [14]

Answer:

MNK = TRP

MN is congruent to TR.

X = 6.3

Step-by-step explanation:

MNK is congruent to TRP because the two triangles are congruent, which is a given statement. This also means that all side and angle measures will be congruent. Because of this, it can be inferred that MN is congruent to TR and they have equal side length measures. This means that TR measures 20. This means that 3X - 1 = 20. By solving we can get 6.33.

7 0
3 years ago
2k - 10 = 6<br><br> Can someone help me I can't figure out the answer
PSYCHO15rus [73]
Hello ! 
 

Okay so what you do is add 10 to the other side

2k - 10 +10 = 6 + 10

You would get .... 

2k = 16

Next you divide 16 by 2 which is 8

and that means 8 is equal to k

K = 8
7 0
4 years ago
Read 2 more answers
Find the next term of this given sequence. 2, 8, 18, 32, 50
musickatia [10]
72 bc 2 plus 6 is 8, 7 plus 10 is 18, 18 plus 14 is 32, 32 plus 18 is 50 and 50 plus 22 is 72!
3 0
3 years ago
Read 2 more answers
A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not
castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

<h3><u>Find P(B)</u></h3>

P(B) = \frac{8}{12}

<h3><u>Find P(B n R)</u></h3>

P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}

<h3><u>Find </u><u> P(R | B)</u></h3><h3>P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}</h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0
4 years ago
!!!!!!!!!!!!!!!100100100100100pts!!!!!!!!!!!!!!!!!!!!!!!!!!
Alex_Xolod [135]
Answers

1. B) 31
2. B) 4
3. A) 15
4. D) 24
5. A) 3

MARK BRAINLEIST PLS THIS TOOK A LOT OF TIME
7 0
3 years ago
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