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MatroZZZ [7]
3 years ago
11

Use the change of Base formula to evaluate log5 92 . then convert. Log5 92 to a logarithm in base 3. Round to the nearest thousa

ndth.
Mathematics
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer:

\log_5 92=2.809

\log_3 2.809=0.940            

Step-by-step explanation:

Given : Expression \log_5 92

To find : Use the Change of Base Formula to evaluate the expression also  convert the expression to a logarithm in base 3?

Solution :  

Applying the change of Base Formula,

i.e. \log_b x=\frac{log_a x}{\log_a b}

We get,

\log_5 92=\frac{\log 92}{\log 5}

\log_5 92=\frac{1.963}{0.698}

\log_5 92=2.809

So, The expression is \log_5 92=2.809

Now, converting the expression to a logarithm in base 3.

Taking log base 3 in 2.809,

\log_3 2.809=\frac{log 2.809}{\log 3}

\log_3 2.809=\frac{0.448}{0.477}

\log_3 2.809=0.940

Therefore, The solution is \log_3 2.809=0.940

vovikov84 [41]3 years ago
4 0
Change of base is
log_a(b)= \frac{log_c(b)}{log_c(a)}
change base to 3
log_5(92)= \frac{log_3(92)}{log_3(5)}
why would you want base 3? base 10 is on most calculators
anyway, the value would be 2.809555
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4 0
3 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
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Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

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3 years ago
Can help me complete this problem please :c
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Answer:

112.5 deg

Step-by-step explanation:

First we find the area of the entire circle.

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A = 16pi m^2

The entire circle has area = 16pi m^2.

The sector has area 5pi m^2.

Now we find the fraction the area of the sector is of the entire circle.

fraction = (5pi m^2)/(16pi m^2) = 5/16 = 0.3125

The full circle has a central angle of 360 deg, the entire circle.

The measure of the central angle of the arc of the sector is the same fraction of the entire circle.

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4 0
3 years ago
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3 years ago
A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

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Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

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s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

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the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

6 0
3 years ago
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