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Marat540 [252]
4 years ago
11

Write the following camparison a ratio reduced to lowest terms. 169 minutes to 8 hours

Mathematics
1 answer:
lorasvet [3.4K]4 years ago
4 0
8 hours is 8*60=480 minutes, so our ratio is 169/480 as a fraction, or 169:480 as a ratio. This is already in lowest terms.
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The sum of five-sixths of f, one-half of p, and 3
Arlecino [84]

Answer:

The expression would look like this: \frac{5}{6}f + \frac{1}{2}p + 3

3 0
3 years ago
Type the correct answer in the box.
lana [24]

Correct question is;

Type the correct answer in the box bellow: If cos x = sin(20 + x)° and 0° < x < 90°, the value of x is ...........

Answer:

x = 35°

Step-by-step explanation:

We are told that;

cos x = sin(20 + x)°

and 0° < x < 90°

From trigonometric identities, we know that;

cos x = sin (90 - x)

Applying to our question gives;

sin (90 - x) = sin (20 + x)°

Comparing both sides, we have;

90 - x = 20 + x

Rearranging;

90 - 20 = x + x

70 = 2x

x = 70/2

x = 35°

7 0
3 years ago
Find the sum of find the sum of 3/4 of 8 1/3 of 4
leonid [27]
3 Divided by 4 is .75
0.75 divided by four is 1/2
1/3 divided bt 4 is 1/12
3/32 + 1/12 is 17/96 (that is in simplest form)
Therefore 
17/96
8 0
4 years ago
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How do you send a picture for answering a question.
Nina [5.8K]
You have to upload it from your computer before you press "ADD YOUR ANSWER"
6 0
3 years ago
Exercise 12.1.2: The probability of an event under the uniform distribution - random permutations. About A class with n kids lin
Nataly [62]

Answer:

a) P_a=\frac{1}{n}

b) P_b=\frac{1}{n(1-n)}

c) P_c=\frac{2}{n}

Step-by-step explanation:

The question is incomplete:

<em>(a) What is the probability that Celia is first in line? (b) What is the probability that Celia is first in line and Felicity is last in line? (c) What is the probability that Celia and Felicity are next to each other in the line?</em>

a) The probability that Celia is first in line, if there are n kids and all of them have the same chance, is 1/n.

P_a=\frac{1}{n}

b) The probability that Celia is first in line and Felicity is last in line is

P_b=\frac{1}{n} \frac{1}{n-1} =\frac{1}{n(1-n)}.

It is deducted like that:

If Celia is placed in the first line (what has a probablity of 1/n), there are left (n-1) kids. Then, the probability of placing Felicity in the last place is 1/(n-1).

Both probabilities multiplied give 1/(n*(n-1)).

c) The probability that Celia and Felicity are next to each other in the line is

P_c=\frac{2(n-1)!}{n!}=\frac{2}{n}

There are n! combinations for kids lines, where (n-1)! permutations have Celia before Felicity and other (n-1)! permutations have Felicity before Celia.

Then, we have 2(n-1)! permutations that have Celia and Felicity next to each other, over n! permutations possible.

5 0
3 years ago
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