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3 years ago

10

Caroline is planting flowers in her garden. She plans her first seven flowers in four minutes. After 12 minutes, she has planted

21 different flowers. Which equation represents this direct variation?

2 answers:

ElenaW [278]3 years ago

5 0

21=f1 I am going out of

Karolina [17]3 years ago

3 0

Answer:

21f=12m

Step-by-step explanation:

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7/35 reducing to the simplest form

nata0808 [166]

Step-by-step explanation:

$\frac{7}{35} = \frac{7}{7 \times 5} = \frac{1}{5} \\$

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I run 1 3/4 miles a day my friend runs 4 times as far as I do gow fae does she run each day s

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Answer:

7 miles per day

Step-by-step explanation:

Turn 1 3/4 in to a decimal (1.75) then multiply by 4 and you will get 7.

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Ice is placed around a bowl of water to lower the temperature. The equation D=−75t+22D=-75t+22 shows the time, t, measured in mi

Serjik [45]

Before cooling begins, the temperature of the water is 22°C.

4 0

3 years ago

Need this for my math test?

docker41 [41]

Answer:

519.6

Step-by-step explanation:

A hexagon has a total of 720 for it's interior angles so each angle is 120 and in the triangle, each of them is 60, making it an equilateral triangle. You can use 30 60 90 triangles to find the height which is 5√3.

(5√3)*10=50√3

The area of the triangle times 6 is 300√3 which is approximately 519.6

7 0

3 years ago

Consider the diagram below. which of the following represents the values x,y and z?

Gemiola [76]

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$

3 0

3 years ago