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4 years ago

Can somebody help moi

Mathematics

2 answers:

Mkey [24]4 years ago

7 0

Answer:

1/10 7/10 dividedby 7 =1/10

Step-by-step explanation:

finlep [7]4 years ago

4 0

Answer:

1/10 cup of frosting

Step-by-step explanation:

If it takes 7/10 cups of frosting to decorate 7 cupcakes, then one cupcake is (7/7)/10=1/10 cup

Proof: 1/10+1/10+1/10+1/10+1/10+1/10+1/10=7/10

Also: 7(1/10)=7/10

Hope that makes sense!

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jannelle is selling lemonade . she has poured 36 cups of lemonade to display. what is an array to show how she displays the cups

baherus [9]

Its dimensions are 4 and 9, or you might say this is a 4 by 9 array. We always mention the rows first and then the columns. The multiplication sentence is

4 × 9 = 36

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4 years ago

I need some help with this question

Hitman42 [59]

Step-by-step explanation:

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2 years ago

A weight-loss clinic advertised that last month its patients, on average,8lb lost . Assuming that average refers to the mean, wh

Ipatiy [6.2K]

Answer:

Given:

A weight-loss clinic advertised that last month its patients, on average, lost 8 lbs

Average refers to mean

a. Last month all of their patients lost at least 8 lbs.

Answer: Mean or average is a measure of central tendency or in other terms refers to the central value of the dataset. If the value of mean/average is 8lb, it signifies that there are some patients who have lost weights more than 8 lbs. So, this statement is False

b. Last month at least one of their patients lost exactly 8 lbs.

Answer: It is a possibility that all the patients have lost their weights greater than or less than 8 lbs. Since the mean is computed by summing up all the values (weight loss in this case) by the total number of observations, it is possible that there can be no patient who has lost exactly 8lbs. So, this statement is False.

c. Two months ago some of their patients lost at least 8 lbs.

Answer: It is clearly mentioned that last month its patients, on average, lost 8 lbs. No information is given about the weight loss of patients before the last month. So, there is not sufficient data to check whether this statement is correct or not.

d. Last month at least one of their patients lost less than 3 lbs.

Answer: It is a possibility that all the patients have lost their weights greater than 3 lbs. Since the mean is computed by summing up all the values (weight loss in this case) by the total number of observations, it is possible that there can be no patient who has lost less than 3lbs. So, this statement is False.

e. Last month, the number of their clients who lost less than 8 lbs was equal to the number of their clients who lost more than 8 lbs.

Answer: Mean is a measure of central tendency which is computed by the diving sum of all observations with the number of all observations (the sum of observations lesser than the mean is compensated by the sum of observations greater than the mean) and for the mean equal to 8lbs, there should be an equal number of people who lost less than 8 lbs and the number of people who lost more than 8 lbs. Hence, this statement is True.

Answer e.Last month, the number of their clients who lost less than 8 lbs was equal to the number of their clients who lost more than 8 lbs is True

7 0

3 years ago

Read 2 more answers

Let a triangle with integer angle measures have one angle of 116°. What is the largest possible angle measure opposite the small

sveta [45]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

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4 years ago