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2 years ago

Evaluate the following expression using the values given:

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

The answer isss.. 15!

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For your own safety, the bank representative says that the following characteristics of PIN numbers are prohibited: (1) all fo

ivanzaharov [21]

Answer:

Total = N(1) +N(2)+N(3) = 10+14+200 = 224 sequences

224 sequences would NOT be permitted.

Step-by-step explanation:

1) all four digits identical

Number of possible PIN with all four digits identical N(1) = 1×1×1×10 = 10 possible PIN

2) sequence of consecutive ascending or descending digits N(2) = 14

Only Ascending starting with 0,1,2 = 3

only descending for 7,8,9 = 3

and both for 3,4,5,6 = (2×4)

Total = 3+3+(2×4) = 14

3) any sequence starting with 19 or 20 (birth years

N(3) = 2 × 1×1×10×10 = 2×100 = 200

N(3) = 200

(Note : 100 possible ways for each of 19 or 20s)

Total = N(1) +N(2)+N(3) = 10+14+200 = 224

224 sequences would NOT be permitted.

7 0

3 years ago

What is the discriminant of the quadratic equation 2x² - x - 3=0?

Tamiku [17]

The given quadratic equation is

$2 {x}^{2} - x - 3 = 0$

comparing with

${ax}^{2} + bx + c = 0$

We get ,

$a = 2 \\ b = - 1 \\ c = - 3$

formula :

$D = {b}^{2} - 4ac \\ \\ D = {( - 1)}^{2} - 4 \times 2 \times ( - 3) \\ \\ D = 1 - ( - 24) \\ \\D = 1 + 24 \\ \\D = 25.$

Discriminant of given quadratic equation is 25 .

option (B) 25 ✔

6 0

1 year ago

Rewrite square root of -49-4

Nataliya [291]

Answer:

$\sqrt{53i}$

Step-by-step explanation:

We need to find $\sqrt{-49-4}$

We know that √-1 = i

Adding -49 and -4 and solving

$\sqrt{-49-4}\\\sqrt{-53}\\\sqrt{53i}$

Since 53 is not a perfect square so our answer is:

$\sqrt{53i}$

7 0

2 years ago

3 x + 2 y = − 6. help me find the y and the x x y -4 0 0 –3

Maru [420]

Answer:

x = 0 and y = -3

Step-by-step explanation:

3 (0) = 0

2 (-3) = -6

So the answer would be x = 0 and y = -3

5 0

3 years ago

Lowest common factor of 28 and 30

Phoenix [80]

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Answer: 2

Explanation:

I hope this helped!

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3 0

3 years ago