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podryga [215]
3 years ago
10

Out of 28 students in a class, 7 have blue eyes. What is the probability a student picked at

Mathematics
2 answers:
mars1129 [50]3 years ago
7 0

Answer:

3/4

Step-by-step explanation:

7/28 have blue eyes

So 28-7=21

21/28 don't have blue eyes

21/28 simplified=3/4

nadya68 [22]3 years ago
4 0

The answer would be 3/5.

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Which point corresponds to the real zero of the graph of y = log3 (x+2) - 1?
brilliants [131]

Answer:

(1, 0 )

Step-by-step explanation:

using the rule of logarithms

log_{b} x = n ⇒ x = b^{n} , then

y = log_{3} (x + 2) - 1

to find the zero let y = 0 , that is

log_{3} (x + 2) - 1 = 0 ( add 1 to both sides )

log_{3} (x + 2) = 1 , then

x + 2 = 3^{1} = 3 ( subtract 2 from both sides )

x = 1

the zero is (1, 0 )

8 0
2 years ago
How to solve question 20? Please help!!
Reptile [31]

Answer:

E. 36 is the answer.

Step-by-step explanation:

27 is a multiple of 9. 9 is 1/3 of 27. Add 9 with 27 to get 36. 9/36 is equal to 1/4. To prove it, multiply 9 with 4 to get 36.

I hope this was clear!

6 0
3 years ago
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
10) Will mark BRAINLIEST + 10 POINTS :)
Mariana [72]
Answer is A.

√6 + √2
----------
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4 0
3 years ago
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Find the value of x for which f(x)=-2
enyata [817]

Answer:

x=2

Step-by-step explanation:

6 0
3 years ago
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