<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
#3 1/6, 1/6, 1/2, 1/3, 5/6.
#4 3/12, 4/12, 5/12, 8/12, 9/12
Step-by-step explanation:
#3 is numbers out of six (fractions).
#4 is the same thing. You add all of the numbers (4, 3, and 5) to get the total and then you subtract to get the probability.
These are all I know.
Answer:
1.3
Step-by-step explanation:
1.33, 1.303, 1.333, 1.3
64*2 is 128
1/2 of a cup of chocolate powder is 64g
laura added 4/6 of a cup
laura went over by 1/3 of a cup
