Algebraic expression represents the statement “4 more than the product of 6 and a number?

1 answer:

7 0

The answer is “6x+4”

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Wittaler [7]

Answer:

0.89

Step-by-step explanation:

6 0

3 years ago

marissa [1.9K]

Answer:

The value of $r=33$ which makes the equation true.

Step-by-step explanation:

Given the equation

$\frac{r}{-11}=-3$

We have to find the value of r for which the equation must be true.

solving the equation

$\frac{r}{-11}=-3$

Multiply both sides by -11

$\frac{r\left(-11\right)}{-11}=\left(-3\right)\left(-11\right)$

$r=33$

Therefore, the value of $r=33$ which makes the equation true.

<u>VERIFICATION:</u>

Putting $r=33$ in the equation

$\frac{r}{-11}=-3$

$\frac{33}{-11}=-3$

$-3=-3$ ∵ $\frac{33}{-11}=-3$

L.H.S = R.H.S

Therefore, the value of $r=33$ which makes the equation true.

7 0

3 years ago

max2010maxim [7]

As for the domain, the only restriction comes from the logarithm. The argument of a logarith must be strictly positive, so we have

$x-2>0 \iff x>2$

As for the range, we have:

The range of $\log(x)$ are all real numbers
If we change to $\log(x-2)$ we're translating the function horizontally, so the range remains the same
If we change to $\log(5(x-2()$ we're stretching the function horizontally, so the range doesn't change
If we change to $\log(5(x-2))+1$ we're translating the function 1 unit up, but the range is already all the real numbers, so it doesn't change.