Answer:
Proved
Step-by-step explanation:
Given: EC || AC, DB || AC, ∠A = ∠F
Prove: ΔMDF ∼ ΔNCA
Solution
See diagram attached to the solution to better understand the following workings.
Redrawing ΔMDF or rotating to be facing the same direction.
EC is parallel to AC
DB parallel to AC
Using similar triangle theorem:
If ΔMDF ∼ ΔNCA
Ratio of Corresponding sides would be equal
(adjacent of ΔMDF)/(adjacent of ΔNCA) = (Opposite of ΔMDF)/(opposite of ΔNCA) = (hypotenuse of ΔMDF)/(hypotenuse of ΔNCA)
DF/ CA = MD/NC = FM/AN
∠A = ∠F
∠M = ∠N
∠D = ∠C
Since the ratio of Corresponding sides and angle are equal, ΔMDF is similar to ΔNCA.
ΔMDF ∼ ΔNCA
The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.
Step-by-step explanation:
The given is,
Compounds money quarterly
Double your money in 10 years
Step:1
Formula to calculate future investment with compounded quarterly,
...............................(1)
Where, A - Future amount
P - Initial investment\
r - Rate of interest
n - No. of compounding in a year
t - No. of years
Step:2
Let, P = X
A = 2X ( Double your money )
From given, n - 4 ( for compounding quarterly )
t - 10 years
From equation (1)



Take root
root on both side,
![\sqrt[40]{2} = (1+\frac{r}{4} )](https://tex.z-dn.net/?f=%5Csqrt%5B40%5D%7B2%7D%20%3D%20%281%2B%5Cfrac%7Br%7D%7B4%7D%20%29)





r = 6.992 %
Result:
The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.
Answer:
20
Step-by-step explanation:
Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²=
[∑X₁² - (( ∑X₁)²/n₁)]=
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!