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4 years ago

Pre Algebra

Mathematics

1 answer:

Maslowich4 years ago

4 0

Answer:

A. 36

B. 3.5

Step-by-step explanation:

To solve for the first equation, we could represent the hot dogs as h(1.75-.50), since they are losing .50 cents for each hot dog, h, they make.

Since they want to know how many hot dogs they have to sell to equal the amount of money they spent, we can represent it as an equal sign.

Now all we have to do is add the constants. Add 12 to our overall equation and subtract 57, since the received $12 in donations and lost $57.

Our equation is 12+h1.75=57+.5h We can just put all of the negative numbers on one side and the positive numbers on the other to find out when they will be equal.

First, subtract 12 from 57.

h1.75=45+.5h

Now subtract .5h from both sides.

h1.25=45

Finally, divide both sides by 1.25.

h=36.

They will have to sell 36 hot dogs.

If they want to sell halve the hotdogs for the same price, simply multiply the current price by 2.

The hotdogs will have to cost $3.5.

Hope this helps!

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Rewrite the system of linear equations as a matrix equation AX = B.

iren2701 [21]

Answer:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]$

And the vector of vriables (X) is:

$\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]$

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

$\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

In conclusion, AX=B is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

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4 years ago

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Answer:

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Step-by-step explanation:

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therefor is it is (3)

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Answer:

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Step-by-step explanation:

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Given that events A and B are independent with P(A)=0.24P(A)=0.24 and P(B|A)=0.85P(B∣A)=0.85, determine the value of P(B)P(B), r

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Answer:

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Step-by-step explanation:

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