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2 years ago

Find roots of 4x^2-2x+9

Mathematics

1 answer:

Korolek [52]2 years ago

4 0

discriminant= b^2-4ac= (-2)^2-4(4)(9)= -140<0

since discriminant <0, graph is always positive, x has no real roots

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The Chen family drove 345.6 miles on their vacation. They drove the same amount each day of the the 3 days. How many miles did t

White raven [17]

Answer:

115.2

Step-by-step explanation:

Take 345.6 miles and divide it by 3 getting your answer. Have a great day!

6 0

1 year ago

Find the angle 0 between the vectors. u=(1, 1, 1, 0), v = (4, 4, 4, 4).

Naya [18.7K]

Answer:

30 degrees

Step-by-step explanation:

u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12

|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)

|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8

cos(theta)=u dot v/(|u||v|)

cos(theta)=12/(sqrt(3)*8)

cos(theta)=3/(sqrt(3)*2)

cos(theta)=sqrt(3)/2

theta=30 degrees

6 0

2 years ago

Can someone give me the answers and step by step instructions please??

professor190 [17]

Answer:

$-1,4,-7,10,...$ neither

$192,24,3,\frac{3}{8},...$ geometric progression

$-25,-18,-11,-4,...$ arithmetic progression

Step-by-step explanation:

Given:

sequences: $-1,4,-7,10,...$

$192,24,3,\frac{3}{8},...$

$-25,-18,-11,-4,...$

To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them

Solution:

A sequence forms an arithmetic progression if difference between terms remain same.

A sequence forms a geometric progression if ratio of the consecutive terms is same.

For $-1,4,-7,10,...$ :

$4-(-1)=5\\-7-4=-11\\10-(-7)=17\\So,\,\,4-(-1)\neq -7-4\neq 10-(-7)$

Hence,the given sequence does not form an arithmetic progression.

$\frac{4}{-1}=-4\\\frac{-7}{4}=\frac{-7}{4}\\\frac{10}{-7}=\frac{-10}{7}\\So,\,\,\frac{4}{-1}\neq \frac{-7}{4}\neq \frac{10}{-7}$

Hence,the given sequence does not form a geometric progression.

So, $-1,4,-7,10,...$ is neither an arithmetic progression nor a geometric progression.

For $192,24,3,\frac{3}{8},...$ :

$\frac{24}{192}=\frac{1}{8}\\\frac{3}{24}=\frac{1}{8}\\\frac{\frac{3}{8}}{3}=\frac{1}{8}\\So,\,\,\frac{24}{192}=\frac{3}{24}=\frac{\frac{3}{8}}{3}$

As ratio of the consecutive terms is same, the sequence forms a geometric progression.

For $-25,-18,-11,-4,...$ :

$-18-(-25)=-18+25=7\\-11-(-18)=-11+18=7\\-4-(-11)=-4+11=7\\So,\,\,-18-(-25)=-11-(-18)=-4-(-11)$

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.

3 0

3 years ago

Which interval for the graphed function contains the local maximum?

photoshop1234 [79]

Answer:

Step-by-step explanation:

5 0

2 years ago

Please explain how to find the answer for this

FromTheMoon [43]

$P(A \textrm{ and } B) = P(A) P(B|A)$

$P(A \textrm{ and } B) = \dfrac{3}{10} \cdot \dfrac{2}{5} = \dfrac{3}{25}$

Second to last choice.

5 0

3 years ago