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Lynna [10]
3 years ago
9

Please help! Question above

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

  • FD and FG
  • vertices

Step-by-step explanation:

For this construction, you want to mark off the distance BC on two segments that are perpendicular to each other. A suitable pair of such segments is FD and FG.

The arcs intersect those segments at points that will become the vertices of the new triangle. Connecting those points will form the hypotenuse of the new triangle. The legs are already drawn as part of segments FD and FG.

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In the xy -coordinate plane, the coordinates of point s are (-2,-6), and coordinates of point T are (18,9). Point Q lies on line
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Answer:

(6,0)

Step-by-step explanation:

The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

(\frac{mx_{2}+nx_{1}}{m+n} ,\frac{my_{2}+ny_{1}}{m+n} )

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).

In this case m will be 2 and n will be 3 as the ratio is 2:3

Using all these values we can find the coordinates of point Q

( \frac{2(18)+3(-2)}{2+3},\frac{2(9)+3(-6)}{2+3} )\\\\ = (\frac{30}{5} ,\frac{0}{5} )\\\\ =(6,0)

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)

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