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nadya68 [22]
3 years ago
7

Which could be the entire interval over which the function f(x) is positive

Mathematics
1 answer:
aalyn [17]3 years ago
7 0

(-\infty,-2) \cup(2,\infty)

<h2>Explanation:</h2>

Remember you need to write complete questions in order to find exact answers. In this way you haven't provided any function, so I'll choose a quadratic function given by:

f(x)=x^2-4x

So we need to find the entire interval at which this function positive. Put another way:

f(x)>0

By using graphing tool, we get the graph shown below. As you can see:

  • The function decreases from x=-\infty \ to \ x=0
  • The function increases from x=0 \ to \ x=\infty
  • The graph of the function is a parabola that opens up.

But what is really importan in this problem is that:

  • The function is positive over the interval (-\infty,-2) \cup(2,\infty)

At this interval the function is positive, that is, f(x)>0

<h2>Learn more:</h2>

Standard equation of the graph of a parabola:

brainly.com/question/12896871

#LearnWithBrainly

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Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

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Step-by-step explanation:

Given,

m∝\frac{1}{r}

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At first we need to find the value of k

Solution

Now,

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