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3 years ago

X + y = 6 x - y = 8 Solve the system of equations.

Mathematics

2 answers:

MatroZZZ [7]3 years ago

4 0

Answer:

x=7

y=-1

Step-by-step explanation:

When the two equations are solved together, they form simultaneous equations.

x+y=6

x-y=8

Let us use the elimination method. if we add the two equations, we eliminate y.

2x=14

x=7

Let us substitute for the value of x obtained above.

x-y=8

7-y=8

y=7-8

y=-1

dusya [7]3 years ago

4 0

The answer to this question is y=-1

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A young person decides to put aside some money for retirement by putting $1,000 in a 30-year savings bond that pays 3.0% simple

Pavel [41]

Answer:

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Step-by-step explanation:

Just use this formula when you have such type of problems:

N = N° (1 + %)^t

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Now let's solve:

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2 years ago

Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔

bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$(x_1, y_1)$ and $(x_2, y_2)$ are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

$h(0) = 3(5)^0 = 3 \cdot 1 = 3$

$h(1) = 3(5)^1 = 3 \cdot 5 = 15$

$h(2) = 3(5)^2 = 3 \cdot 25 = 75$

$h(3) = 3(5)^3 = 3 \cdot 125 = 375$

Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

$m = \dfrac{15 - 3}{1 - 0} = \boxed{12}$

<u>Section B</u>

$m = \dfrac{375 - 75}{3 - 2} = \boxed{300}$

Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

$\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25$

It is 25 times greater. This is because $3(5)^x$ is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.