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Semenov [28]
4 years ago
10

A b c or d pls helpp

Mathematics
1 answer:
allochka39001 [22]4 years ago
3 0

Answer:

C (0, 9)

Step-by-step explanation:

First, X is reflected across the line x=2.

X(4, -7) becomes X'(0, -7).

Next, X' is reflected across the line y=1.

X'(0, -7) becomes X"(0, 9).

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Find the equation of the line through point (3,−3) and parallel to y=3x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/
exis [7]

Answer:

y =3x - 12

Step-by-step explanation:

I'm fairly certain this is the answer.

Consider the point (3,-3). In terms of variables this is written (x,y).

Remember that the equation for slope is y = mx + b.

In that equation, "b" is your y-intercept, and "m" is your slope.

If 2 lines are parallel, they have the same slope but different y-intercepts. So you can use the slope from the equation y=3x-4 to find the parallel line. You can also plug in the values 3 and -3 to solve for b, our y-intercept.

If we set up the equation, we have -3 = 3(3) + b.

Now solve for b.

-3 = 9 + b

Combine like terms, so that -12 = b, and you have your y-intercept.

To create the equation, take out the coordinate pair that the line passes through, and only have the SLOPE and the Y-INTERCEPT showing in the equation.

Therefore, y = 3x - 12

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3 years ago
Which of the following functions best represents the graph?
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Please help asap
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Simplify this problem
ikadub [295]

Answer:

\boxed{  \frac{ \sqrt[3]{ {x}^{11} } }{4} }

Step-by-step explanation:

=  >  \frac{ {x}^{4} }{ \sqrt[3]{64x} }  \\  \\  =  >  \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} }  )\times  ({x}^{ \frac{1}{3} } )}  \\  \\  =  >  \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times(  {x}^{ \frac{1}{3} }  )}  \\  \\  =  >   \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times  \frac{1}{ \cancel{3}} } ) \times(  {x}^{ \frac{1}{3} }  )}   \\  \\  =  >  \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4 -  \frac{1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{12 - 1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{11}{3} } }{4}  \\  \\  =  >   \frac{ \sqrt[3]{ {x}^{11} } }{4}

7 0
3 years ago
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