HIGH SCHOOL LEVEL) SUPER EASY I JUST AM DUMB, PLEASE HELP

Mathematics

1 answer:

bazaltina [42]3 years ago

3 0

Answer:

Step-by-step explanation:

-8p-20+8p=-11

-20==-11

THERE IS NI SOLUTİON

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Work out m and c for the line: y = 10 x

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ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

$L=W+3$

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As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

$\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}$

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We can find the roots using the quadratic formula:

$\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}$

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

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