Set a proportion. They are similar triangles.
A school is selling tickets to a drama performance. On the first day of ticket sales the school sold 3 adult tickets and 1 child
1 answer:
Answer:
System of linear equations
a: adult ticket price and c: child ticket price
Step-by-step explanation:
This system of equations can be used to find the price of the adult and child tickets.
We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).
Let a: adult ticket price and c: child ticket price,
we have for the first day that 3 adult tickets and 1 child ticket adds $38:
and for the second day we have that 2 adult tickets and 2 child tickets adds $52:
If we write this as a system of equations, we have:
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Answer:
see the attached
Step-by-step explanation:
In the attachment, we will refer to the circles, bottom-to-top, as circles 1, 2 and 3. The black points of intersection, bottom-to-top, will be referred to by the letters A, B, C, D. The transversal line through the white point (W) and pink point (P) will be line q.
Step 1. Draw line q through point P so it intersects line m at some convenient point. Label that point W.
Step 2. Choose an arbitrary radius for your compass. Here, we have chosen it to be the length WB. It happens to be less than half the length of WP, but that is not a requirement.
Step 3. Draw an arc of the chosen radius centered at W and intersecting line q and line m. Label the intersection points A (on line m) and B (on line q). These intersection points are on circle 1.
Step 4. Draw an arc of the same radius centered at P. It should be a long enough arc that it would intersect the proposed line parallel to m. Label the intersection point on line q with label C. This intersection point is on circle 3.
Step 5. Adjust the compass width (radius) to the distance from A to B. This is the radius of circle 2.
Step 6. Draw an arc centered at C so that it intersects the arc of Step 4. This is circle 2, and you want it to intersect circle 3. Label that point of intersection D.
Step 7. Draw line PD parallel to m.
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The point of the construction is to create congruent alternate interior angles AWB and CPD, so that lines AW and PD are parallel.
In 90 minutes the population to grow to 700 organisms.
Given that,
A strand of bacteria has a doubling time of 15 minutes.
If the population starts with 10 organisms.
We have to determine,
How long would it take for the population to grow to 700 organisms?
According to the question,
A strand of bacteria has a doubling time of 15 minutes.
If the population starts with 10 organisms.
In 15 minutes strand of bacteria has a doubling time the population starts with 10 organisms.
In 15 minutes 20 bacteria for the population to grow.
In 30 minutes strand of bacteria has a doubling time the population starts with 20 organisms.
In 30 minutes 40 bacteria for the population to grow.
In 45 minutes strand of bacteria has a doubling time the population starts with 40 organisms.
In 45 minutes 80 bacteria for the population to grow.
In 60 minutes strand of bacteria has a doubling time the population starts with 80 organisms.
In 60 minutes 160 bacteria for the population to grow.
In 75 minutes strand of bacteria has a doubling time the population starts with 160 organisms.
In 75 minutes 320 bacteria for the population to grow.
In 90 minutes strand of bacteria has a doubling time the population starts with 320 organisms.
In 90 minutes 640 bacteria for the population to grow.
In 120 minutes strand of bacteria has a doubling time the population starts with 640 organisms.
In 120 minutes 1280 bacteria for the population to grow.
Hence, In 90 minutes the population to grow to 700 organisms.
For more details refer to the link given below.