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Sonbull [250]
2 years ago
15

A school is selling tickets to a drama performance. On the first day of ticket sales the school sold 3 adult tickets and 1 child

ticket for a total of $38. On the second day, the school sold 3 adult tickets and 2 child tickets for a total of $52.
Which of the following system of linear equations could model this situation?
Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

System of linear equations

\left\{\begin{matrix} 3a+c=38 \\\\   3a+2c=52 \end{matrix}\right.

a: adult ticket price and c: child ticket price

Step-by-step explanation:

This system of equations can be used to find the price of the adult and child tickets.

We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).

Let a: adult ticket price and c: child ticket price,

we have for the first day that 3 adult tickets and 1 child ticket adds $38:

3a+1c=38

and for the second day we have that 2 adult tickets and 2 child tickets adds $52:

3a+2c=52

If we write this as a system of equations, we have:

\left\{\begin{matrix} 3a+c=38 \\\\   3a+2c=52 \end{matrix}\right.

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miskamm [114]

Answer:

21square feet

Step-by-step explanation:

Count the whole squares first.

if each square is one square foot then 18 whole squares will be 18×1= 18 square feet

add halves (aproximate halves) together. (3 in total)

Therefore A= 18 +3

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3 0
2 years ago
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Solve 3(x-4)=-5 for x​
makvit [3.9K]

Answer:

x=7/3

Step-by-step explanation:

3(x-4)=-5

3x-12=-5

3x=7

x=7/3

8 0
2 years ago
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Mr. Paulsen challenges Olivia and Angelica to move figure ABCDE onto figure A"B"C"D"E" using a series of two different transform
Jobisdone [24]

Problem 1

One method Olivia could have used is to reflect over the x axis and then translate 10 units to the right.

Let's apply these set of steps to point C.

C = (-2,-4)

C' = (-2,4) after reflecting over the x axis; y coordinate flips in sign

C'' = (8,4) after shifting to the right 10 units; add 10 to the x coordinate

Point C(-2,-4) moves to C''(8,4) which is shown in the diagram. I'll let you check the other four points.

-----------

Another method Olivia could have used is to shift to the right 10 units first, then reflect over the x axis. In this case, the order doesn't matter. Though for some other combinations of transformations, order does matter.

============================================================

Problem 2

Reflecting over the y axis will have the point (x,y) turn into (-x,y). Only the x coordinate changes, and we flip the sign here. The y coordinate stays the same.

A point like C(-2,-4) becomes C'(2,-4) after the y axis reflection. Shifting up 8 units means we add 8 to the y coordinate to arrive at C''(2,4) but this does not match what the diagram shows. Therefore, Angelica's method is incorrect.

You should find other inconsistencies for the other four points as well.

============================================================

Problem 3

Michael's method isn't correct either. He does not apply an x axis reflection and instead relies entirely on translations to move ABCDE to A''B''C''D''E''

At a quick glance, it looks like Michael may be correct. But upon a much closer look, you'll see that things don't line up perfectly.

Instead of point C, we'll pick on point D this time.

D is located at (-6,-2). If we shift up 8 units, then we add 8 to the y coordinate to get to D'(-6,6). Then add 10 to the x coordinate to shift 10 units to the right. This leads us to D''(4,6).

However, the diagram shows D'' is actually at (4,2)

I'll let you check the other points. You should find that only points C and E go to the correct locations, but the other points do not. Again, this is because Michael did not apply an x axis reflection. His figure of A''B''C''D''E'' is upside down compared to what it should be.

============================================================

To summarize, the methods described in problem 1 are the correct way to get ABCDE to move to A''B''C''D''E''. If Olivia followed either of those two methods, then she is correct. Both Angelica and Michael have incorrect methods.

5 0
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tigry1 [53]
Sense -4 and +2 would be 6 digits away from each other, we would then have to figure out, what would 4 times x - 2 would equal "x".

We would do, 4×2 = 8.

8 - 2 = 6.

Sense 6 is the amount of how much -4 and +2 would be from each other, this would then mean that x would then equal 8.

\boxed{x=8}

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3 years ago
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shutvik [7]
The maximum height is yo<span> = 0</span>
When the projectile is at its maximum height <span> v</span>y = 0.
Note that the maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. :)
6 0
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