Question

The circle below is centered at the point (5,3) and has a radius of length 4. What is it’s equation

Answer 1

${x}^{2} + {y}^{2} - 10x - 6y + 18 = 0$

Answer 2

Answer:

$(x-5)^2 + (y-3)^2= 16$ is the equation of a circle

Step-by-step explanation:

The circle below is centered at the point (5,3) and has a radius of length 4

To find the center  form of equation, we use formula

$(x-h)^2 + (y-k)^2= r^2$

where (h,k) is the center and 'r' is the radius of the circle

given center is (5,3)

h=5  and k =3

radius r= 4, plug in all the values in the equation

$(x-h)^2 + (y-k)^2= r^2$

$(x-5)^2 + (y-3)^2= 4^2$

$(x-5)^2 + (y-3)^2= 16$ is the equation of a circle