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saw5 [17]
3 years ago
7

The circle below is centered at the point (5,3) and has a radius of length 4. What is it’s equation

Mathematics
2 answers:
Mkey [24]3 years ago
6 0

{x}^{2}  +  {y}^{2}  - 10x - 6y + 18 = 0

KonstantinChe [14]3 years ago
5 0

Answer:

(x-5)^2 + (y-3)^2= 16 is the equation of a circle

Step-by-step explanation:

The circle below is centered at the point (5,3) and has a radius of length 4

To find the center  form of equation, we use formula

(x-h)^2 + (y-k)^2= r^2

where (h,k) is the center and 'r' is the radius of the circle

given center is (5,3)

h=5  and k =3

radius r= 4, plug in all the values in the equation

(x-h)^2 + (y-k)^2= r^2

(x-5)^2 + (y-3)^2= 4^2

(x-5)^2 + (y-3)^2= 16 is the equation of a circle

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