Answer:
is the equation of a circle
Step-by-step explanation:
The circle below is centered at the point (5,3) and has a radius of length 4
To find the center form of equation, we use formula
![(x-h)^2 + (y-k)^2= r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%20%2B%20%28y-k%29%5E2%3D%20r%5E2)
where (h,k) is the center and 'r' is the radius of the circle
given center is (5,3)
h=5 and k =3
radius r= 4, plug in all the values in the equation
![(x-h)^2 + (y-k)^2= r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%20%2B%20%28y-k%29%5E2%3D%20r%5E2)
![(x-5)^2 + (y-3)^2= 4^2](https://tex.z-dn.net/?f=%28x-5%29%5E2%20%2B%20%28y-3%29%5E2%3D%204%5E2)
is the equation of a circle