0.92 , 0.479 , 0.387 , 0.2
[See the last first digit after the decimal. I chose 0.92 since 9 is the greater than 2,3 and 4]
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Answer:
Option (B)
Step-by-step explanation:
From the given table,
With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.
Interval (0, 1) lies in the domain of the function in which the y-values of the function are,
At x = 0,
f(0) = -6
At x = 1,
f(1) = 0
Therefore, values of the given function are increasing in the interval of (0, 1).
Option (B) will be the correct option.
Use pythagorean theorem
c2 = a2 + b2
c2 = 1.5^2 + 2^2
c2 = 2.25 + 4
c2 = 6.25
c = 2.5