Answer:
Area of ABCD = 45.1 cm²
Step-by-step explanation:
From the figure attached,
Area of ABCD = Area of ΔBCD + Area of ΔABD
Area of ΔABD =
sin(55°) =
sin(55°) =
AB = 10sin(55°)
AB = 8.19 cm
cos(55°) =
=
AD = 10cos(55°)
AD = 5.74cm
Area of ΔABD =
= 23.51 cm²
Area of ΔBCD =
=
tan(38°) =
BE =
Similarly, DE =
Since, BE + DE = 10 cm
CE(1.28 + 1.04) = 10
CE(2.32) = 10
CE = 4.31 cm
Area of ΔBCD =
= 21.55 cm²
Area of ABCD = Area of ΔBCD + Area of ΔABD
= 21.55 + 23.51
= 45.06
≈ 45.1 cm²
<h2>
Answer with explanation:</h2>
Let p be the true proportion of registered voters wish to see Mayor Waffleskate defeated.
As per given , we have
Sample size : n= 447
Number of of registered voters wish to see Mayor Waffleskate defeated = 157
I.e. sample proportion :
Confidence interval for population proportion is given by :-
, where n= sample size
= sample proportion
z* = critical z-value.
Critical z-value for 98% confidence interval is 2.33. (By z-table)
Then, the 98% confidence interval for the proportion of registered voters who wish to see Waffleskate defeated will be :
Since the 0.27 < 0.299 , it means 0.27 does not belong to the above confidence interval.
So , we reject the null hypothesis ().
So , <u>98% confidence interval does not support the claim.</u>
Tan(x) = 12/39
X = 17 degrees
Answer is C