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Vedmedyk [2.9K]
3 years ago
7

An Expression Is Shown: 625.2 ÷ 5.5 What Is The Value Of The Expression?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
113.6727272727273 this is the answer I got but you could also write it as 113.68 hope this helps
Reika [66]3 years ago
3 0
113.6727272727273 that's the answer for the value of your expression.
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Which expression gives the measure of angle ABC?​
kirza4 [7]
The answer is D!

If helped mark me the brainiest!!
6 0
3 years ago
Find the flux of F = x^3 i  + y^3 j  + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4
givi [52]
Use the divergence theorem. Let R be the cylindrical region, then

\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV

(where \mathbf n denotes the unit normal vector to \partial R, but we don't need to worry about it now)

We have

\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}
\nabla\cdot\mathbf F=3x^2+3y^2+3z^2

For the solid R with boundary \partial R, we can set up the following volume integral in cylindrical coordinates for ease:

\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz
=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz
=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz
=352\pi
5 0
3 years ago
the value of y is inversely proportional to the value of x when y=42, x=6. what is the value when x=9
iren [92.7K]
Hello,

y=k/x
if x=6 then y=42==>42=k/6==>k=252
if x=9 then y=252/9=28

4 0
3 years ago
What is 1/7 -3/4 plz help
Ahat [919]
So in order to subtract you need a common denominator. So you multiply 3/4 by 7 and 1/7 by 4 and get 7/28 - 21/28 then you subtract and get - 14/28 or -1/2 if you want to simplify it.
3 0
3 years ago
Read 2 more answers
Simplify and write the answer in exponential form 3x^4 × y^4 x^4​
RideAnS [48]

Answer:

The simplified expression in the exponential form will be: 3x^8y^4

Step-by-step explanation:

Given the expression

3x^4\times \:y^4x^4

simplifying the expression and writing the answer in exponential form

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}

x^4x^4=x^{4+4}

so the expression becomes

3x^4\times \:y^4x^4=3x^{4+4}y^4

                    =3x^8y^4           ∵ \mathrm{Add\:the\:numbers:}\:4+4=8

Therefore, the simplified expression in the exponential form will be: 3x^8y^4

6 0
3 years ago
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